We know that
[volume of the prism]=L*W*H
L=x²*y in
W=x in
H=y² in
[volume of the prism]=(x²*y)*(x)*(y²)-----> x³*y³ in³
the answer is
x³*y³ in³
Answer:
m/100 x 8
Step-by-step explanation:
-3x^2 - 10x + 5 = 0
Quadratic formula:
-b +/- sqrt[b^2 - 4(a)(c)]/2(a)
So. . . 10 +/- sqrt[(10^2) - 4(-3)(5)]/2(-3)
10 +/- sqrt[100+60]/ -6
10 +/- sqrt[160]/-6
Answer:
-2w^2 - 5w + 7
Step-by-step explanation:
Just the values with the same powers of w
(3w^2-5w^2)+(-7w+2w)+(6+1)
-2w^2 - 5w + 7
7.) Area of a square pyramid is given by A = s^2 + 2sl; where s is the side length of the base and l is the slant height.
Area of given pyramid = 4^2 + (2 x 4 x 7) = 16 + 56 = 72 ft^2
8.) Area of the given pyramid is the area of the hexagonal base plus the area of the six slant triangles.
Area of hexagonal base = (3sqrt(3))/2 x 10^2 = 150 x 1.732 = 259.8
Area of the 6 traingles = 6(1/2 x 10 x 13) = 6 x 65 = 390
Total surface area of the pyramid = 259.8 + 390 = 649.8 ≈ 650 m^2
9.) Using pythagoras rule, the slant height is sqrt(6^2 + 3.5^2) = sqrt(36 + 12.25) = sqrt(48.25) = 6.9 mm
10.) The surface area of a cone is given by πr^2 + πrl
Area = π x 6^2 + π x 6 x 20 = 36π + 120π = 490.1 cm^2
11.) l = sqrt(r^2 + h^2) = sqrt(11^2 + 16^2) = sqrt(121 + 256) = sqrt(377) = 19m
