PLEASE HELP ASAP

Mathematics

2 answers:

hoa [83]2 years ago

8 0

Answer:

Step-by-step explanation:

D, -9, 62.85, 6.28x100(628)

Zina [86]2 years ago

4 0

Answer:

Step-by-step explanation:

The answer would be C

Since of course negative 5 is a negative and any negative number plus a positive number would end up being a negative number and that means that that would be the least since no other number is a negative. The square root of 132.... Can it be bigger than 7 5/16? Yeah. Because the Square root of 132, if rounded, it would be 11 which 11 is greater than 7 which would mean the correct order would be -5 x 10^2, 7 5/16, and the square root of 132.

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Median mode mean and range on 84 45 10 28 75 63 16 55

GREYUIT [131]

PUT THIS SET IN ORDER FROM LEAST TO GREATEST:

10, 16, 28, 45, 55, 63, 75, 84
__________________
MEDIAN: Find the number in the middle of the set.
10, 16, 28, 45, 55, 63, 75, 84
There cannot be two medians, so you find the number between 45 & 55.
MEDIAN = 50
_________________
MEAN: Find the average by adding up all of the numbers and dividing them by how many numbers there are.
10 + 16 + 28 + 45 + 55 + 63 + 75 + 84 = 376
376/8 = 47
MEAN = 47
________________
MODE: The number that occurs most often. If no number repeats, there's no mode.
THERE IS NO MODE
________________
RANGE: The difference between the largest and smallest value in the set. Subtract the largest (84) and smallest (10) value.
84 - 10 = 74
RANGE = 74

6 0

4 years ago

Read 2 more answers

Help omggg help omgg

kenny6666 [7]

Answer:

Θ = 84°

Step-by-step explanation:

using the identity

cosx = sin(90 - x) , then

cos6° = sin(90 - 6)° = sin84°

that is Θ = 84°

4 0

2 years ago

The diagram shows a hexagon-shaped tile used for flooring. Each hexagon tile has an area of 18/3 in 2 Find x.

mylen [45]

Answer:

x = 12

Step-by-step explanation:

The hexagonal tile given here is made up of 6 triangles with equal bases and heights.

So, area of hexagonal tile will be equal to 6 times the area of one triangle.

Therefore,

$18 \sqrt{3} = 6 \times \frac{1}{2} \times 2 {( \sqrt{3)} }^{ \frac{x}{12} } . {( \sqrt{3)} }^{ \frac{x}{6} } \\ \\ 18 \sqrt{3} = 6 {( \sqrt{3)} }^{ \frac{x}{12} } . {( \sqrt{3)} }^{ \frac{2x}{12} } \\ \\ \frac{18 \sqrt{3} }{6} = {( \sqrt{3)} }^{ \frac{x}{12} + \frac{2x}{12} } \\ \\ 3 \sqrt{3} = {( \sqrt{3)} }^{ \frac{3x}{12} } \\ \\ 3. {3}^{ \frac{1}{2} } = {3}^{ \frac{3x}{24} } \\ \\ {3}^{1 + \frac{1}{2} } = {3}^{ \frac{x}{8} } \\ \\ {3}^{ \frac{3}{2} } = {3}^{ \frac{x}{8} } \\ (bases \: are \: equal \: so \: exponents \: \\ will \: also \: be \: equal) \\ \implies \frac{3}{2} = \frac{x}{8} \\ \\ x = \frac{3 \times 8}{2} \\ \\ x = 3 \times 4 \\ \\ x = 12$