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Leona [35]
3 years ago
13

The Math Club is raising money so they can attend a local competition next month. They have already raised $125 and they are sel

ling candy bars to raise the rest of the money needed. Each candy bar sells for $2.50.
Mathematics
1 answer:
prisoha [69]3 years ago
3 0

Answer: 100 candy bars

Step-by-step explanation:

You did not include the question but judging by the progression I can assume that the question is along the lines of how many candy bars they will need to sell to reach their target.

You did not include the amount they have to raise as well so let us assume that number is $375.

Assuming they have to raise $375 and they have already raised $125, the amount left to be raised is:

= 375 - 125

= $250

With each candy bar selling at $2.50, the number of candy bars they will need to sell is:

= 250/ 2.50

= 100 candy bars

<em>You should use this process to find the answer to your question. </em>

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Leni [432]

SOLUTION

From the sequence give

–3, 1, 5, 9, . . .

The first term, a = -3

The common difference, d = 4 (gotten by adding 4 to the next term).

The number of terms required n = 6.

Formula for sum of an arithmetic sequence is given by

S_n=\frac{n}{2}\lbrack2a+(n-1)d\rbrack

Substituting these values into the equation above we have

\begin{gathered} S_n=\frac{n}{2}\lbrack2a+(n-1)d\rbrack \\ S_6=\frac{6}{2}\lbrack2\times-3+(6-1)4\rbrack \\ S_6=3\lbrack-6+(5)4\rbrack \\ S_6=3\lbrack-6+20\rbrack \\ S_6=3\lbrack14\rbrack \\ S_6=42 \end{gathered}

Hence, the answer is 42, option B

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Answer:

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Answer:

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3 years ago
Every prime number greater than 10 has a digit in the ones place that is include in wich set of numbers A- 1,3,7,9 B-1,3,5,9 D-1
marta [7]

That's very interesting.  I had never thought about it before.
Let's look through all of the ten possible digits in that place,
and see what we can tell:

-- 0:
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-- 1:
    A number greater than 10 with a 1 in the units place could be
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-- 2:
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-- 3:
   A number greater than 10 with a 3 in the units place could be
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-- 4: 
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-- 5:
   A number greater than 10 with a 5 in the units place is a multiple
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-- 6:
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-- 7:
   A number greater than 10 with a 7 in the units place could be
   a prime (17, 37 etc.) but it doesn't have to be (27, 57) .

-- 8:
   A number greater than 10 with a 8 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 9:
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   a prime (19, 29 etc.) but it doesn't have to be (39, 69) .

So a number greater than 10 that IS a prime number COULD have
any of the digits  1,  3,  7,  or  9  in its units place.

It CAN't have a  0,  2,  4,  5,  6,  or  8 .

The only choice that includes all of the possibilities is  'A' .

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