17 is the correct answer.
(a+b)^7= a^7+ 7a^7b+ 21 a^6b²+ 35a^5b³+ 35 a⁴b⁴+ 21 a³b^5 + 7a²b^6 + b^7
Answer: A. Repeated results if the player makes 75% of his shots in the long run.
Step-by-step explanation:
The null distribution is always the opposite of the alternative distribution which in most cases represents the claim or hypothesis which is to be tested or performed. In the scenario given, the challenge is to show that a basketball player has an average higher than that of the NBA. NBA average stands at 75%. The alternative hypothesis is the claim, which is ;
H1 : μ > 75%
THE null is thus :
H0 : μ = 75% ; which means that repeated result of the player will yields an average of 75%
2/5 of 50 is 20. 50-20=30. Making FG=30
