Simplify 19 – 1.67x + (

A rocking horse has a weight limit of 60pounds. What percentage of the weight limit is 33 pounds? What percentage of the weight

bixtya [17]

Answer:

The percentage is 55% when weight limit is 33 pounds.

The percentage is 190% when weight limit is 114 pounds.

The 95% of the limit weighs 57 pounds.

Step-by-step explanation:

Given:

Weight limit of rocking horse = 60 pounds.

We need to find:

a) What percentage of the weight limit is 33 pounds.

b)What percentage of the weight limit is 114 pounds.

c) What weight is 95% of the limit.

Now Solving for a we get;

Weight limit = 33 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{33}{60}\times100 = 55\%$

Hence The percentage is 55% when weight limit is 33 pounds.

Now Solving for b we get;

Weight limit = 114 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{114}{60}\times100 = 190\%$

Hence The percentage is 190% when weight limit is 114 pounds.

Now Solving for c we get;

Percentage Weight = 95%

Now Amount of weight limit can be calculated by multiplying Percentage weight limit with total weight limit and then Dividing by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{95}{100}\times60 = 57 \pounds$

Hence The 95% of the limit weighs 57 pounds.

4 0

3 years ago

Can someone please help me?

yaroslaw [1]

3√24= 3√2^2*6 = 3*2√6 = 6√6

2√384= 2√8^2*6 = 2*8√6 = 16√6

√96= √4^2*6 = 4√6

6√6 -16√6- 4√6 = -14√6

Final answer: -14√6

4 0

3 years ago

Please help!

erik [133]

For the answer to the question above,
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3

1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 

1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 

1 + 9x + 36x^2 + 84x^3 

In my experience, up to the x^3 is often adequate to approximate a route. 

(1+x) = 0.98 

x = 0.98 - 1 = -0.02 

Substituting: 

1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 

approximation = 0.834 

Checking the real value in your calculator: 

(0.98)^9 = 0.834 

So you have approximated correctly. 

If you want to know how accurate your approximation is, write out the result of each in full: 

1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 

 (0.98)^9 = 0.8337477621 

So it is correct to 4

5 0

2 years ago

Read 2 more answers

Good morning everyone! Can someone please tell me if the answer I got for this question is correct. I'm not sure and I wanna mak

Vika [28.1K]

Answer:

80 degrees.

Step-by-step explanation:

The arc PS = 2 * the angles subtended by PS ( that is < PRS)

= 2 * 40 = 80 degrees.

5 0

3 years ago