Please help!

C = k - 273.15 (a) Write two other related equations . (b) If the temperature is 23 in degrees Celsius , what is the temperature

Alona [7]

Answer:

(a) k = C + 273.15, F = 1.8(k - 273.15) + 32

(b) k = 296.15

(c) 25 celcius is greater than 300 kelvis.

Step-by-step explanation:

(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.

C = k - 273.15

C + 273.15 = k

k = C + 273.15

F = 1.8(k - 273.15) + 32

(b) for this one you have to substitute in the previous equation and solve for k.

23 = k - 273.15

k = 23 + 273.15

k = 296.15

(c) you have to convert either kelvins to celcius or celcius to kelvins.

C = k - 273.15

C = 300 - 273.15

C = 26.85

So 25 celcius is greater than 300 kelvis.

5 0

3 years ago

What is the sum of series is numbers 64&66 ?<br> Using the summation notation

iragen [17]

Answer:

64. 6138

66. 8.078125

Step-by-step explanation:

Let's take it one number at a time.

For number 64:

$6(2)^{1-1}=6$

$6(2)^{2-1}=12$

$6(2)^{3-1}=24$

$6(2)^{4-1}=48$

$6(2)^{5-1}=96$

$6(2)^{6-1}=192$

$6(2)^{7-1}=384$

$6(2)^{8-1}=768$

$6(2)^{9-1}=1536$

$6(2)^{10-1}=3072$

Sum = 6 + 12 + 24 + 48 + 96 + 192 + 384 + 768 + 1536 + 3072

Sum = 6138

For number 66:

$12(-\frac{1}{2})^{0}=12$

$12(-\frac{1}{2})^{1}=-6$

$12(-\frac{1}{2})^{2}=3$

$12(-\frac{1}{2})^{3}=-1.5$

$12(-\frac{1}{2})^{4}=0.75$

$12(-\frac{1}{2})^{5}=-0.375$

$12(-\frac{1}{2})^{6}=0.1875$

$12(-\frac{1}{2})^{7}=-0.0078125$

$12(-\frac{1}{2})^{8}=0.046875$

$12(-\frac{1}{2})^{9}=-0.0234375$

Sum = 12 + -6 + 3 + -1.5 + 0.75 + -0.375 + 0.1875 + -0.0078125 + 0.046875 + -0.0234375

or to make things simpler:

Sum = 12 - 6 + 3 - 1.5 + 0.75 - 0.375 + 0.1875 - 0.0078125 + 0.046875 - 0.0234375

Sum = 8.078125

4 0

3 years ago

How to add fractions with different denominators and negative numbers?

Kisachek [45]

Let find the least of common multiple = LCM it’s for the denominators.
Multiple of the numerator then the denominator to get the denominators
Don’t forget to to add the numerator but leave the denominators the same

8 0

3 years ago

There were 326 students at the high school dance. There were 24 more girls than boys. How many girls and boys attended?

abruzzese [7]

Answer:

187 girls 139 boys

Step-by-step explanation:

first you divide 326 by 2 to get 163, and then you add 24 to it to find how many girls and then you subtract 24 from it to find how many boys

4 0

3 years ago

Read 2 more answers

Petes boat can travel 48 miles upstream in 4 hours. The return trip takes 3 hours. Find the speed of the boat in still water and

tankabanditka [31]

So... hmm bear in mind, when the boat goes upstream, it goes against the stream, so, if the boat has speed rate of say "b", and the stream has a rate of "r", then the speed going up is b - r, the boat's rate minus the streams, because the stream is subtracting speed as it goes up

going downstream is a bit different, the stream speed is "added" to boat's
so the boat is really going faster, is going b + r

notice, the distance is the same, upstream as well as downstream
thus $\bf \begin{cases}
b=\textit{rate of the boat}\\
r=\textit{rate of the river}
\end{cases}\qquad thus
\\\\\\

\begin{array}{lccclll}
&distance&rate&time(hrs)\\
&----&----&----\\
upstream&48&b-r&4\\
downstream&48&b+4&3
\end{array}
\\\\\\

\begin{cases}
48=(b-r)(4)\to 48=4b-4r\\\\
\frac{48-4b}{-4}=r\\
--------------\\
48=(b+r)(3)\\
-----------------------------\\\\
thus\\\\
48=\left[ b+\left(\boxed{\frac{48-4b}{-4}}\right) \right] (3)
\end{cases}$

solve for "r", to see what the stream's rate is

what about the boat's? well, just plug the value for "r" on either equation and solve for "b"

5 0

3 years ago