The scale on a drawing is 1 cm = 4.5 meters. If the length of the drawing is 6.2 cm, what is the actual length in meters?

Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and pr

Minchanka [31]

Answer:

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98[/tex[ or 98%Step-by-step explanation:A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". The margin of error is the range of values below and above the sample statistic in a confidence interval. Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". [tex]p_1$ represent the real population proportion for 1

$\hat p_1 =0.768$ represent the estimated proportion for 1

$n_1=92$ is the sample size required for 1

$p_2$ represent the real population proportion for 2

$\hat p_2 =0.646$ represent the estimated proportion for 2

$n_2=95$ is the sample size required for 2

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

For this case we have the confidence interval given by: (-0.0313,0.2753). From this we can find the margin of erro on this way:

$ME= \frac{0.2753-(-0.0313)}{2}=0.1533$

And we know that the margin of erro is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

We have all the values except the value for $z_{\alpha/2}$

So we can find it like this:

$0.1533=z_{\alpha/2} \sqrt{\frac{0.768(1-0.768)}{92} +\frac{0.646 (1-0.646)}{95}}$

And solving for $z_{\alpha/2}$ we got:

$z_{\alpha/2}=2.326$

And we can find the value for $\alpha/2$ with the following excel code:

"=1-NORM.DIST(2.326,0,1,TRUE)"

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98$ or 98%

7 0

3 years ago

After working for 25 hours lammer made $375 after working 40 hours lammer made $600 predict how much will he make after 10 hours

Alex

25hr. 40h. 10hr

375$ 600$ x

25 . 40 . x = 1000
375 . 600 = 225000
225000÷1000
x = 225

3 0

3 years ago

Please help me ASAP thank you

Allisa [31]

101+ 6x-5=180

6x=84

x=14

hope this helps!

5 0

3 years ago

Read 2 more answers

4. IF AABD ACBE, find the value of x. 27 cm 12 cm SE E 23.4 cm

snow_tiger [21]

Answer:

$x = 10.4$

Step-by-step explanation:

Since ∆ABD is similar to ∆CBE, therefore, the ratio of their corresponding side lengths would be equal to each other. Thus:

$\frac{BD}{BE} = \frac{AD}{CE}$

BD = 12 cm

BE = x

AD = 27 cm

CE = 23.4 cm

Plug in the values

$\frac{12}{x} = \frac{27}{23.4}$

Cross multiply

$x \times 27 = 23.4 \times 12$

$27x = 280.8$

Divide both sides by 27

$x = 10.4$

6 0

3 years ago

Thomas is training for a race by running on a circular path. He knows that it is 0.75 mile

kifflom [539]

The tree to the edge of the path acts as a radius. use the formula to find a circles perimeter to find the length of the path, which is 2r(pi). 2r=1.5, so multiple that by pi. if pi is simplified to 3.14, the circumference of the circle/length of the path would be 4.71 miles.

4 0

3 years ago