Your problem statement needs a bit of correction:

"<span>Y= -16t^2 +400, where t represents the number OF SECONDS after the camera is dropped. How long will it BE before Kay sees the splash from the camera hitting the water?"

Set y = -16t^2 + 400 = 0. We assume that 400 and 0 represent feet (English system).

Then 16t^2 = 400, and so 25 = t^2. Only the positive square root makes sense here, and that root is 5 (seconds).</span>

3 0

3 years ago

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For the month of March in a certain city, 57% of the days are cloudy. Also in the month of March in the same city, 55% of the da

oksian1 [2.3K]

Answer: 0.9649

Step-by-step explanation:

Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.

Given : For the month of March in a certain city, the probability that days are cloudy : $P(A)=0.57$

Also in the month of March in the same city,, the probability that the days are cloudy and rainy : $P(A\cap B)=0.55$

Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-

$P(B|A)=\dfrac{P(A\cap B)}{P(A)}$

$\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}$

Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649

4 0

3 years ago

Solve for x:<br><br> x + 3 = 8

artcher [175]

How generous
x+3=8
minus 3 both sides
x+3-3=8-3
x+0=5
x=5

5 0

3 years ago