57, 66, 75, 84, 93.... find the 250th term of the sequence
2 answers:
Each term adds 9 to the previous term.
The first term is 57, and to find the 250th term, we'd add 9 a total of 249 times.
That's the same as adding 9 times 249, which is 2241.
57 + 2241 = 2298.
(By the way, you can represent any term
of this equation with the expression 
. What we do is count one step back to find our "zeroth" term, per se, and then each addition is represented as 9 times the n. This could also be 
.)
The first term is 57, and to find the 250th term, we'd add 9 a total of 249 times.
That's the same as adding 9 times 249, which is 2241.
57 + 2241 = 2298.
(By the way, you can represent any term
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Answer:
6 possible integers
Step-by-step explanation:
Given
A decreasing geometric sequence
Required
Determine the possible integer values of m
Assume the first term of the sequence to be positive integer x;
The next sequence will be
The next will be;
The nth term will be
For each of the successive terms to be less than the previous term;
then must be a proper fraction;
This implies that:
<em>Where 7 is the denominator</em>
<em>The sets of </em><em> is </em>
<em> and their are 6 items in this set</em>
<em>Hence, there are 6 possible integer</em>