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3 years ago

Please help IM SO CONFUSED!

Mathematics

1 answer:

rodikova [14]3 years ago

4 0

Answer:

Step-by-step explanation:

You can see from the table that 2 bracelets are made every 30 minutes.

There are 9 intervals of 30 minutes each in 4.5 hours.

So, the number of bracelets that are made in 4.5 hours is

9x2=18

Another way to see this is to note from the table that 4 bracelets are made in 60 minute, which is 1 hour. So, in 4 hours, 16 bracelets will be made. Also, from the table, 2 bracelets are made in 30 minutes, which is 1/2 hour. So, adding up, 18 bracelets are made in 4.5 hours.

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64 POINTS

Mekhanik [1.2K]

L(t)=9-0.5t
t=time in hours,
L(t)=length of candle at time t

(A) substitute t=1,2,3,4,5,6 respectively to get
(1,8.5)
(2,8)
(3,7.5)
(4,7)
(5,6.5)
(6,6)

(B) it is a function because none of the x-values duplicate, (nor the y-values).

(C) If the rate changes to 0.45 "/hr, the relation is still linear.
All linear function with finite slope are functions.

7 0

3 years ago

Read 2 more answers

For what value of x is this equation true? 10x−2(x+6)=52 10x−2(x+6)=52 A x=5 x=5 B x=5 3 4 x=534 C x=7 1 9 x=719 D x=8 x=8For wh

insens350 [35]

Answer:

x = 8

Step-by-step explanation:

10x - 2 (x + 6) = 52

Let X become 8

10 (8) - 2 (8 + 6) = 52

80 - 2 (14) = 52

80 - 28 = 52

52=52

7 0

3 years ago

How many pennies are in 1 months lion dollars?

My name is Ann [436]

Ten thousand pennies

5 0

3 years ago

Read 2 more answers

6th grade math help me, please:))

Leokris [45]

Answer:

40 percent

Step-by-step explanation:

(10/25 ) x 100 = (2/5) x100 = (0.4) x 100 = 40% of the roses was given away.

7 0

3 years ago

Read 2 more answers

Tomika heard that the diagonals of a rhombus are perpendicular to each other. Help her test her conjecture. Graph quadrilateral

Stella [2.4K]

Answer:

a. The four sides of the quadrilateral ABCD are equal, therefore, ABCD is a rhombus

b. The equation of the diagonal line AC is y = 5 - x

The equation of the diagonal line BD is y = 5 - x

c. The diagonal lines AC and BD of the quadrilateral ABCD are perpendicular to each other

Step-by-step explanation:

The vertices of the given quadrilateral are;

A(1, 4), B(6, 6), C(4, 1) and D(-1, -1)

a. The length, l, of the sides of the given quadrilateral are given as follows;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

The length of side AB, with A = (1, 4) and B = (6, 6) gives;

$l_{AB} = \sqrt{\left (6-4 \right )^{2}+\left (6-1 \right )^{2}} = \sqrt{29}$

The length of side BC, with B = (6, 6) and C = (4, 1) gives;

$l_{BC} = \sqrt{\left (1-6 \right )^{2}+\left (4-6 \right )^{2}} = \sqrt{29}$

The length of side CD, with C = (4, 1) and D = (-1, -1) gives;

$l_{CD} = \sqrt{\left (-1-1 \right )^{2}+\left (-1-4 \right )^{2}} = \sqrt{29}$

The length of side DA, with D = (-1, -1) and A = (1,4) gives;

$l_{DA} = \sqrt{\left (4-(-1) \right )^{2}+\left (1-(-1) \right )^{2}} = \sqrt{29}$

Therefore, each of the lengths of the sides of the quadrilateral ABCD are equal to √(29), and the quadrilateral ABCD is a rhombus

b. The diagonals are AC and BD

The slope, m, of AC is given by the formula for the slope of a straight line as follows;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Therefore;

$Slope, \, m_{AC} =\dfrac{1-4}{4-1} = -1$

The equation of the diagonal AC in point and slope form is given as follows;

y - 4 = -1×(x - 1)

y = -x + 1 + 4

The equation of the diagonal AC is y = 5 - x

$Slope, \, m_{BD} =\dfrac{-1-6}{-1-6} = 1$

The equation of the diagonal BD in point and slope form is given as follows;

y - 6 = 1×(x - 6)

y = x - 6 + 6 = x

The equation of the diagonal BD is y = x

c. Comparing the lines AC and BD with equations, y = 5 - x and y = x, which are straight line equations of the form y = m·x + c, where m = the slope and c = the x intercept, we have;

The slope m for the diagonal AC = -1 and the slope m for the diagonal BD = 1, therefore, the slopes are opposite signs

The point of intersection of the two diagonals is given as follows;

5 - x = x

∴ x = 5/2 = 2.5

y = x = 2.5

The lines intersect at (2.5, 2.5), given that the slopes, m₁ = -1 and m₂ = 1 of the diagonals lines satisfy the condition for perpendicular lines m₁ = -1/m₂, therefore, the diagonals are perpendicular.

5 0

3 years ago