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Andrews [41]
3 years ago
7

Use all four operations and at least one exponent to write an expression that has a value of 100.

Mathematics
1 answer:
OleMash [197]3 years ago
3 0

Answer: 5 to the 2 power x4+100 divide by 2

Step-by-step explanation:

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Jeff and his cousin work during the summer for a roofing company. Jeff's cousin has been working
sdas [7]

Answer:

1

Step-by-step explanation:

doesn't work hard enough

3 0
3 years ago
Read 2 more answers
8 (40+7) = ( 8. ) + (8 7
prohojiy [21]
The first part is 8 x 40=320
8 x 7=56
320+56 and i am not sure what you have going on on the other half
8 0
3 years ago
The model includes a new park in the center of the city. If the dimensions of the
11111nata11111 [884]

The question is incomplete. Here is the complete question.

As a part of city building refurbishment project,  architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.

The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?

Answer: 81 feet by 153 feet

Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.

In the refurbishment project, the unit scale is given by

1 inch = 9 feet

So, the dimensions of the new park in actual dimensions would be

1 inch = 9 feet

9 inches = x

x = 9.9

x = 81 feet

1 inch = 9 feet

17 inches = y

y = 17.9

y = 153 feet

The actual dimensions of the new park are 81 feet by 153 feet.

6 0
2 years ago
Approximately what is the mean of this set of data?
PIT_PIT [208]
It should be d which is 45
8 0
3 years ago
HOW MANY BASEBALLS CAN FIT INTO THE TRACTOR TRAILER. THE TRAILER DIMENSIONS ARE 301.5"L X 96.99"W X 105.04"H AND CIRCUMFERENCE R
Shkiper50 [21]
Volume of tractor = length x width x height = 301.5 x 96.99 x 105.04 = 3,071,630.624

For baseballs of 9 inches:
9=2\pi r \\  \\ r= \frac{9}{2\pi}

Volume = \frac{4}{3} \pi r^3= \frac{4}{3} \pi \left( \frac{9}{2\pi} \right)^3=12.31

Number of 9 inches baseballs = \frac{3,071,630.624}{12.31} = 249,513

For baseballs of 9.25 inches:
9.25=2\pi r \\  \\ r= \frac{9.25}{2\pi}

Volume = \frac{4}{3} \pi r^3= \frac{4}{3} \pi \left( \frac{9.25}{2\pi} \right)^3=13.37

Number of 9.25 inches baseballs = \frac{3,071,630.624}{13.36} = 229,824

Therefore, the tractor can contain between 229,824 and 249,513 baseballs.
8 0
2 years ago
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