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exis [7]
2 years ago
14

Stem-and-leaf plots provide a way to graphically compare​ data, unlike histograms.​ However, they are more difficult to construc

t. B. ​Stem-and-leaf plots can compare quantitative data to qualitative​ data, unlike histograms.​ However, they are not very useful for large data sets. C. ​Stem-and-leaf plots are easier to make and can contain more information than histograms.​ However, they are not very useful for large data sets. D. ​Stem-and-leaf plots are more useful for large data sets and can display more information than histograms.​ However, they are more difficult to construct.
Mathematics
1 answer:
IgorLugansk [536]2 years ago
7 0

Question:

Discus the advantages and disadvantages of histograms versus stem-and-leaf plots

Answer:

C. Stem-and-leaf plots are easier to make and and can contain more information than histograms. However, they are not very useful for large data sets

Step-by-step explanation:

A stem and leaf plot is a graphical presentation of quantitative data similar to an histogram. However, a stem and leaf plot retains and present the values of the original in the data set such that individual data values can be seen and can then be used to make analysis

The stem and leaf plot consists of a stem and a leaf  arranged in the order of place value, such that the numbers having a common highest place value are arranged on a row in a stem and leaf plot and therefore a stem and leaf plot is easier to make or construct than an histogram

However, it is very rare to find stem and leaf plots having more than 50 datasets or observations.

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Keep in mind that you can gather only like terms. Two terms can be summed/subtracted if they involve the same powers of the same variables.

So, going point by point:

  1. We can subtract the terms, because they both involve the variable b, and we have 3b-7b = (3-7)b = -4b
  2. We can sum the terms, because they all involve the variable a, and we have a+a-5a = (1+1-5)a = -3a
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If 11250 = m(600) + b and 7650 = m(400) + b, how do I find the values of b and m? I forgot how to compare when I have two differ
Lelu [443]

Answer:

b=450 and m=18

Step-by-step explanation:

This exercise is an example of <em>linear system equations</em>. A <em>system of linear equations</em> is a set of (linear) equations that have more than one unknown. The unknowns appear in several of the equations, but not necessarily in all of them. What these equations do is relate the unknowns to each other.

The easy way to solve this problem is by using the<em> reduction method</em>.The <em>reduction method</em> consists of operating between the equations, such as adding or subtracting both equations, so that one of the unknowns disappears. Thus, we obtain an equation with a single unknown.

Ordering the equations as a system equations.

\left \{ {{600m+b=11250} \atop {400m+b=7650}} \right.

Using the reduction method, let's substract the second equation with the first equation, in order to clear m.

600m + b = 11250

<u>-400m -  b = -7650</u>

200m       = 3600    -------->  m = 3600/200 -----> m = 18

We can substitute the value of m in any of the two equations to obtain the unknow b.

Let's substitute the value of m in the second equation.

400(18) + b = 7650

7200 + b = 7650 -----> b = 7650 - 7200 -------> b = 450

We can check this values in both equations.

600m + b = 11250 -----> 600(18) + 450 = 11250

400m + b = 7650 ----->  400(18) + 450 = 7650

Satisfying the result of both equations.

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