A financial analyst wanted to estimate the mean annual return on mutual funds. A random sample of 60 funds' returns shows an average rate of 12%. If the population standard deviation is assumed to be 4%, the 95% confidence interval estimate for the annual return on all mutual funds is
A. 0.037773 to 0.202227
B. 3.7773% to 20.2227%
C. 59.98786% to 61.01214%
D. 51.7773% to 68.2227%
E. 10.988% to 13.012%
Answer: E. 10.988% to 13.012%
Step-by-step explanation:
Given;
Mean x= 12%
Standard deviation r = 4%
Number of samples tested n = 60
Confidence interval is 95%
Z' = t(0.025)= 1.96
Confidence interval = x +/- Z'(r/√n)
= 12% +/- 1.96(4%/√60)
= 12% +/- 0.01214%
Confidence interval= (10.988% to 13.012%)
To answer this item, we let x and y be the amounts (in mL) of the red and the brown dyes, respectively. The equations that would allow us to answer the question are,
x + y < 200
x ≤ 2y
The values of x and y in the inequalities are therefore 133.33 mL and 66.67 mL.
Answer:
1a. y-intercept: 12
1b. slope: -3/2
1c. equation: y = -3/2x +12
2a. y-intercept: -9
2b. slope: 2
2c. equation: y = 2x -9
Step-by-step explanation:
<h3>1.</h3>
A) We observe the pattern to be <em>x-values in the table increase by 2, while y-values in the table decrease by 3</em>. We notice the first x-value is 2, so extending the table upward to x=0 would tell us the y-intercept. That is, adding 3 to the first y-value will give the y-intercept as (x, y) = (0, 12).
B) We have already observed that the "rise" (change in y) is -3 for each "run" (change in x) of 2. The slope is the ratio of these changes:
slope = m = rise/run = -3/2
C) From the above, we know that m=-3/2 and b=12. Putting these values into the equation for the line gives ...
y = -3/2x +12
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<h3>2.</h3>
A) We observe the pattern to be <em>y-values increase by 2 while x-values increase by 1</em>. As before, we can find the point that would go before the first one shown in the table. It will have an x-value of 0 and a y-value of -9.
the y-intercept is -9
the slope is 2/1 = 2
the equation is y = 2x -9
The distance is increasing at a rate that is the speed of the plane multiplied by the cosine of the angle between its flight path and the direct line to the radar station. That cosine is 4/√(3²+4²) = 4/5, so the distance is increasing at
440 mi/h × 4/5 = 352 mi/h