See the attached figure.
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AB = 10 , FD = 3
∵ D is the midpoint of AB, and F is the mid point of CB
∴ FD // AC , FD = 0.5 AC
∵ Δ ABC is a right triangle at C
∴ FD ⊥ BC
∴ BD = 0.5 AB = 5
∴ in Δ FDB ⇒⇒ BF² = BD² - FD² = 5² - 3² = 16
∴ BF = √16 = 4
∵ F is the mid point of CB
∴ CF = BF = 4 , and CB = 2 BF = 2*4 = 8
∵ D is the midpoint of AB, and E is the mid point of AC
∴ DE // CB , and DE = 0.5 CB = 0.5 * 8 = 4
∴ T<span>he length of line ED is 4
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30a^2b^4 GCF = 2
24ab^3 GCF = 3
Answer:
43.25-7-(t*1.15)
Step-by-step explanation:
because oBaMa
Answer:
The answer to your question is: A = 282.6 in²
Step-by-step explanation:
Data
height = 9 in
radius = 5 in
Formula
A = 2πrh
Process
A = 2(3.14)(5)(9)
A = 282.6 in²