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stellarik [79]
2 years ago
9

Help Please :C :c :c :c

Mathematics
2 answers:
Delvig [45]2 years ago
5 0

Answer: What do u need help even with theres no choices

Step-by-step explanation:

natali 33 [55]2 years ago
3 0

Answer:

is there any answers choices or is it like a typing???

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Put the following portions in order from least to greatest 30% 1/5 75% 5/6
sertanlavr [38]

Answer:

1/5,30%,75%,5/6

Step-by-step explanation:

first turn all of them in to decimals:

1/5=0.20

30%=0.30

75%=0.75

5/6=0.83

then put the decimals in order from least to greatest

done!

8 0
2 years ago
Fast Freddie is a widget assembler. He is paid $3.27 for every widget he assembles. What is Freddie's total pay for a week in wh
Brums [2.3K]
If he is paid 3.27 for every widget assembled...and he assembles 209...then his total pay for the week is : 3.27 * 209 = $ 683.43 <==
3 0
3 years ago
Read 2 more answers
NEED HELP QUICK!!! WILL GIVE LIKE
AVprozaik [17]
Don’t open the link give you a virus
8 0
2 years ago
I will give brainliest to whoever gets this correct.
Oxana [17]

Answer:

0

Step-by-step explanation:

I'll comment if you need an explanation! Hope this helps! :)

5 0
2 years ago
The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance,
tensa zangetsu [6.8K]

We have the following data set:

2,7,15,3,12,9,15,8,3,10

The range is the difference between the highest and lowest values in the set, to find the range, order the data set from least to greatest.

2,3,3,7,8,9,10,12,15,15

Then,

\begin{gathered} \text{Range}=15-2 \\ \text{Range}=13 \end{gathered}

Mean is represented by the following expression:

\text{Mean}=\frac{\text{Sum of all data points}}{Number\text{ of data po}ints}\text{Mean}=\frac{84}{10}=8.4

Population variance formula looks like this:

\begin{gathered} \sigma^2=\frac{\sum^{}_{}(x-\mu)^2}{N} \\ \text{where,} \\ \sigma^2=\text{population variance} \\ \sum ^{}_{}=addition\text{ of} \\ x=\text{each value} \\ \mu=population\text{ mean} \\ N=\text{ number of values in the population} \end{gathered}

Then, substituting:

\begin{gathered} \sigma^2=\frac{(2-14)^2+(3-14)^2+\cdots+(15-14)^2}{10} \\ \sigma^2=20.44 \end{gathered}

For the standard deviation:

\begin{gathered} s=\sqrt[]{\frac{\sum ^{}_{}(x-\mu)^2}{N}} \\ s=4.521 \end{gathered}

5 0
1 year ago
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