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lisabon 2012 [21]
3 years ago
13

How to find x(x-2)<0

Mathematics
2 answers:
Anna [14]3 years ago
7 0

Answer:

x<2

Step-by-step explanation:

x- 2 <0

x < 2

MakcuM [25]3 years ago
7 0

Answer:

0

Step-by-step explanation:

Hi there!

x(x-2)

Set x(x-2) equal to 0:

x(x-2)=0

Solve for <em>x </em>by using the zero product property:

x(x-2)=0

x=0 and x=2

Now, we know that for the inequality x(x-2), one of the following must be true:

1) 0

2) x or x>2

To find out which one it is, 1) or 2), we can substitute a value into x(x-2) to see if the inequality is true.

For example, 1 takes place in between 0 and 2. If 1 satisfies x(x-2), then 0 must be true. If it does not, then x or x>2 must be true:

1(1-2)

This inequality is true. Thus, 0.

I hope this helps!

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What sum can be expressed as 6(3 + 9)?
Vera_Pavlovna [14]
Hey there!

Let's keep our goal in mind. We're looking fo a sum, which means a number plus a number, or the answer to that problem.

In order to simplify this, we need to use the distributive property which can be defined as:

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Now, we can use this forumula to express:

6(3+9) = 6(3) = 6(9) = 18 + 54 = 72

Hope this helps!
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Step-by-step explanation:

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A function <img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D" id="TexFormula1" title="f(x)=\sqrt[3]{x}" alt="f(
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Answer:

a reflection in the x-axis, and a vertical translation of 8 units down.

Step-by-step explanation:

The given function is

f(x) =  \sqrt[3]{x}

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We can see that the transformation is of the form

- f(x) - h

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And the negation tells us that the parent function is reflected in the x-axis

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