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3 years ago

Answer both questions please

Mathematics

1 answer:

ollegr [7]3 years ago

8 0

He first answer is: <1 and <4 <2 and <3
I can’t see all of question 2

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How do I solve this?

Aleksandr-060686 [28]

First you have to set up your equation. 5x+80 and x+15.

8 0

3 years ago

Read 2 more answers

Someone please help me answer at least one of these problems it’s really hard and it’s due by tomorrow and I really don’t get it

Serga [27]

For 5 and 6 : 5 would be 144 when you put 3 in the position of the t . And 6 would be 1,024 when you put 8 where the t is .

5 0

4 years ago

Find 2 numbers a and b such that (a-b)^2 < (a+b)(a-b)< (a+b)^2 Find two numbes a and b such that this is not true

Svet_ta [14]

Suppose for the moment that the inequality holds for all $a,b$ :

$(a-b)^2$

Expanding everything gives

$a^2-2ab+b^2$

$\implies-ab$

In particular, the inequality says that $-ab$ for any choice of $a,b$ . But if $a$ and $b>0$ , then $-ab>0$ while $ab$ .

So one possible choice of $a,b$ could be $a=-1$ and $b=1$ . Then we get

$(-1-1)^2=4$

$(-1+1)(-1-1)=2$

$(-1+1)^2=0$

but clearly it's not true that $4$ .

8 0

3 years ago

Solve for h..-6.2h - 1.2= 0.86

Arada [10]

Answer:

Step-by-step explanation:

-6.2h-1.2=0.86

-6.2h=2.06

h=-103/310

5 0

3 years ago

A University has 30,600 students think school counselor estimates that 2% of the students break three on my languages in a rando

xxTIMURxx [149]

Answer:

Counselor's estimate isn't correct.

Step-by-step explanation:

Total number of students in university = 30,600

2% break 3 of the languages

Therefore, 2/100 × 30600 = 612 students break 3 of the languages in the University according to the counselor.

In a random sample of 240 students, 20 break 3 of the languages.

% = 20/240 × 100 = 8.33%

SinceTotal number of students = 30,600

Therefore, 30,600/240 = 127.5

Which means 127.5 × 20 = 2550.

Which means 2550 students break 3 of the languages as against the 612 students stated by the counselor.

4 0

3 years ago