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Romashka-Z-Leto [24]

3 years ago

7

Use PEMDAS to evaluate the expression 24 ÷ 3 + 6 x 4 − 11. 19 21 22 24 asap

2 answers:

Kipish [7]3 years ago

7 0

Answer:

21

Step-by-step explanation:

PEMDAS= Parenthesis Exponents Multiplication Division Addition Subtraction

Hope this helps! have a great day!

monitta3 years ago

4 0

Answer:

The answer is 21 if you use PEMDAS.

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11.57-n=7.51 write the unknown number for n

shusha [124]

It is true and stands for 4.06

7 0

3 years ago

Read 2 more answers

Jana ran the first 3 and a half miles of a 5 mile race in 1 3rd of an hour. what was her average rate, in mph, for the first par

Lisa [10]

Answer:

always try to draw a diagram first

Step-by-step explanation:

Jana ran The first 3.5 miles in 1/3 of an hour. remember the problem tells us that we want our answer in miles per hour or mph. so we have to set up our problem so that our units match in the end. The diagram above shows 3.5 mi over 1/3 hour. so we must divide 3.5 miles by 1/3 hour

note:

$3 \frac{1}{2} mi = \frac{7mi}{2}$

therefore

$\frac{7mi}{2} \: \div \: \frac{1hr}{3} =$

$\frac{7mi}{2} \times \frac{3}{1hr} = \frac{21mi}{2hr} = 10 \frac{1}{2} \frac{mi}{hr}$

7 0

3 years ago

please help me to solve this word problems leading to quadratic equation: A girl is 6 years younger than her brother. the produc

vova2212 [387]

Answer:

Brother is 70.5 and sister is 64.5

Step-by-step explanation:

you will need to set up a simple equation and give out variables.

Girls age = 6-x

Brother's age= x

the you will take those 2 and add them and place them equal to 135:

6-x+x=135

6-2x+6=135+6

The 6 cancels out

2x=141

2x/2=141/2

x=70.5

The brother's age would be 70.5 then and the girl's would be 64.5

5 0

3 years ago

which will have a higher effective interest rate a payday loan for $1700 that is due in 16 days with a fee of $100, or a payday

Fantom [35]

1700 that is due in 14 days with a fee of 100$ because it’s a shorter time period

7 0

3 years ago

Read 2 more answers

. Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P. Side QR = 17m, diagonal QS

trapecia [35]

Answer:

495 meter²

Step-by-step explanation:

In the given kite QRST,

PQ = PS = 15 meter

QR = 17 meter

We have to find the area of the kite.

Since kite is in the form of a rhombus.

and rhombus is = $\frac{1}{2}$ (Diagonal QS) × (Diagonal RT)

In Δ QRP,

17² = 15² + RP²

$\sqrt{17^{2}-15^{2}} = RP$

$RP=\sqrt{289-225}$

= √64 = 8 meters.

So RT = RP + PT = 8 + 25 = 33 meter.

Now area of kite = $\frac{1}{2}$ (30) (33) = 495 meter²

6 0

3 years ago