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vova2212 [387]
2 years ago
13

Jana ran the first 3 and a half miles of a 5 mile race in 1 3rd of an hour. what was her average rate, in mph, for the first par

t of the race? explain how you solve the problem.
7.RP.1, 7.NS.3
Mathematics
1 answer:
Lisa [10]2 years ago
7 0

Answer:

always try to draw a diagram first

Step-by-step explanation:

Jana ran The first 3.5 miles in 1/3 of an hour. remember the problem tells us that we want our answer in miles per hour or mph. so we have to set up our problem so that our units match in the end. The diagram above shows 3.5 mi over 1/3 hour. so we must divide 3.5 miles by 1/3 hour

note:

3 \frac{1}{2} mi =  \frac{7mi}{2}

therefore

\frac{7mi}{2}  \:  \div  \:  \frac{1hr}{3}  =

\frac{7mi}{2}  \times  \frac{3}{1hr}  =  \frac{21mi}{2hr}  = 10 \frac{1}{2}  \frac{mi}{hr}

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22 meters per second in kilometers per hour.
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Answer:

79.2 kilometres per hour

Step-by-step explanation:

1 km = 1000 m

1 hr = 3600 sec. To convert km/hr into m/sec,

We multiply the speed which in this case is 22m/s

by 3.6 giving 79.2 kmh. Therefore 22m/s into kilometer is 79.2 kmh.

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2 years ago
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1 over 100 is already simplified.
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John drove to Daytona Beach, Florida, in hours. When he returned, there was less traffic, and the trip took only hours. If John
olga55 [171]

Question: John drove to a distant city in 5 hours.

When he returned, there was less traffic and the trip took only 3 hours.

If John averaged 26 mph faster on the return trip, how fast did he drive each way

Answer:

For the first trip he drove at a speed of 39 mph

For the second trip he drove at a speed of 65 mph

Step-by-step explanation:

Let the distance for both journey be Z because they are equal.

Let the speed for the first journey be X

Let the speed of the second journey be Y

Formula for speed = distance ÷ time

For the first journey the speed X = Z ÷ 5

For the second journey the speed Y = Z ÷ 3

Since John averaged 26 mph faster in the second trip than the first trip due to traffic, it means that the difference in speed between the first & second trip is 26 mph

Difference in speed = (Z÷3) - (Z÷5) = 26

subtracting both results to  (5Z-3Z) ÷ 15 = 26

Upon cross multiplication

2Z = 390

Z = 390÷2 = 195 miles

Therefore speed for first journey = 195 ÷ 5 = 39 mph

Speed for second journey = 195 ÷ 3 = 65 mph

To verify, 65 - 39 = 26 mph

8 0
3 years ago
A number times four is six less than twice the number find the number
icang [17]

Answer:

The number is -3

Step-by-step explanation:

First, let's translate the statement into an equation.

  • 4x = 2x - 6

Step 1: Subtract 2x from both sides.

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Step 2: Divide both sides by 2.

  • 2x/2 = -6/2
  • x=-3

Therefore, the number is -3/

6 0
2 years ago
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