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Burka [1]
2 years ago
9

Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step

s below. What was Jada’s error?
Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction
Negative StartFraction 4 over 9 EndFraction (Negative StartFraction 9 over 4 EndFraction) = StartFraction x over 108 EndFraction (Negative StartFraction 9 over 4 EndFraction)
x = negative StartFraction 1 over 48 EndFraction

Jada should have multiplied both sides of the equation by 108.
Jada should have multiplied both sides of the equation by Negative StartFraction 4 over 9 EndFraction.
The product of Negative StartFraction 9 over 4 EndFraction and StartFraction 1 over 108 EndFraction is not equal to Negative StartFraction 1 over 48 EndFraction.
The product of Negative StartFraction 9 over 4 EndFraction and 108 should have been the value of x.
Mark this and return

Mathematics
2 answers:
zavuch27 [327]2 years ago
6 0

Answer:first option

Step-by-step explanation:

I taked test

Lilit [14]2 years ago
3 0

Answer: First option.

Step-by-step explanation:

The complete exercise is attached.

In order to solve this exercise, it is necessary to remember the following property:

The Multiplication property of Equality states that:

If\ a=b\ then\ a*c=b*c

In this case, the equation that Jada had is the folllowing:

-\frac{4}{9}=\frac{x}{108}

Jada needed to solve for the variable "x" in order to find its value.

The correct procedure to solve for for "x" is to multiply both sides of the equation by 108. Then, you get:

(108)(-\frac{4}{9})=(\frac{x}{108})(108)\\\\-48=x

As you can notice in the picture, Jada did not multiply both sides of the equation by 108, but multiplied the left side by -\frac{4}{9}<em>  </em>and the right side by -\frac{9}{4}.

Therefore,you can conclude that Jada should have multiplied both sides of the equation by 108.

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Solve for g. Show your work! g+6-3=31
Zielflug [23.3K]

Answer:

g=28, that may not be how the teacher would want you to show your work, but that's how I find the answer!

Step-by-step explanation:

6-3=3

31-3=28

28=g

So therefore 28+6-3=31

6 0
3 years ago
Carmen works at a pet store.To feed 8 cats, she empties four 6-ounce cans of cat food into a large bowl.Carmen divides the food
balu736 [363]

Answer:

0.75 oz

Step-by-step explanation:

8 cats divided by 6-oz cans=0.75 oz each

7 0
3 years ago
In triangle , side and the perpendicular bisector of meet in point , and bisects . If and , what is the area of triangle
stich3 [128]

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, 145–√5  is the area of a triangle.

I supposed here that [ABD] is the perimeter of ▲ ABD.

As  BD  is a bisector of  ∠ABC ,

ABBC=ADDC=97

Let  ∠B=2α

Then in isosceles  △DBC

∠C=α

BC=2∗DC∗cosα=14cosα

Thus  AB=18cosα

The Sum of angles in  △ABC  is  π  so

∠A=π−3α

Let's look at  AC=AD+DC=16 :

AC=BCcosC+ABcosA

16=14cos2α+18cosαcos(π−3α)

[1]8=7cos2α−9cosαcos(3α)

cos(3α)=cos(α+2α)=cosαcos(2α)−sinαsin(2α)=cosα(2cos2α−1)−2cosαsin2α=cosα(4cos2α−3)

With  [1]

8=cos2α(7−9(4cos2α−3))

18cos4−17cos2α+4=0

cos2α={12,49}

First root lead to  α=π4  and  ∠BDC=π−∠DBC−∠C=π−2α=π2 . In such case  ∠A=π−∠ABD−∠ADB=π4, and  △ABD  is isosceles with  AD=BD. As  △DBC  is also isosceles with  BD=DC=7,  AD=7≠9.

Thus first root  cos2α=12  cannot be chosen and we have to stick with the second root  cos2α=49. This gives  cosα=23  and  sinα=5√3.

The area of a triangle ABD=12h∗AD  where h  is the distance from  B  to  AC.

h=BCsinC=14cosαsinα

Area of  triangle ABD=145–√5

= 145–√5.

Incomplete question please read below for the proper question.

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, what is the area of triangle ABD?

Learn more about the Area of the triangle at

brainly.com/question/23945265

#SPJ4

6 0
2 years ago
Nia is training for a marathon. Her average speed during training so far is 7.1 miles per hour. if she runs ar that rate for tra
Burka [1]

Answer:

about 10 my boy

Step-by-step explanation:

big big big

6 0
2 years ago
_ABC is a right triangle where m_B = 90Á. The coordinates of A and B are (5, 0) and (2, 5), respectively. If the x-coordinate of
Leokris [45]
Since the triangle is a right triangle at point B, then line AB is perpendicular to line BC.
For perpendicular lines, the product of their slopes is -1.
Slope of AB = (5 - 0)/(2 - 5) = 5/-3 = -5/3
Slope of BC = (y - 5)/(7 - 2) = (y - 5)/5

-5/3(y - 5)/5 = -1
-5(y - 5)/15 = -1
-5(y - 5) = -15
y - 5 = 3
y = 3 + 5 = 8

Therefore, the y-coordinate of point C is 8.
4 0
3 years ago
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