part A)
![\bf \begin{array}{|c|cccccc|ll} \cline{1-7} x&8&27&64&125&&x\\ \cline{1-7} y&\stackrel{\sqrt[3]{8}}{2}&\stackrel{\sqrt[3]{27}}{3}&\stackrel{\sqrt[3]{64}}{4}&\stackrel{\sqrt[3]{125}}{5}&&\sqrt[3]{x} \\ \cline{1-7} \end{array}~\hspace{10em}y = \sqrt[3]{x}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Ccccccc%7Cll%7D%20%5Ccline%7B1-7%7D%20x%268%2627%2664%26125%26%26x%5C%5C%20%5Ccline%7B1-7%7D%20y%26%5Cstackrel%7B%5Csqrt%5B3%5D%7B8%7D%7D%7B2%7D%26%5Cstackrel%7B%5Csqrt%5B3%5D%7B27%7D%7D%7B3%7D%26%5Cstackrel%7B%5Csqrt%5B3%5D%7B64%7D%7D%7B4%7D%26%5Cstackrel%7B%5Csqrt%5B3%5D%7B125%7D%7D%7B5%7D%26%26%5Csqrt%5B3%5D%7Bx%7D%20%5C%5C%20%5Ccline%7B1-7%7D%20%5Cend%7Barray%7D~%5Chspace%7B10em%7Dy%20%3D%20%5Csqrt%5B3%5D%7Bx%7D)
part B)
f(x) = 10 + 20x
so if you rent the bike for a few hours that is
1 hr.............................10 + 20(1)
2 hrs..........................10 + 20(2)
3 hrs..........................10 + 20(3)
so the cost is really some fixed 10 + 20 bucks per hour, usually the 10 bucks is for some paperwork fee, so you go to the bike shop, and they'd say, ok is 10 bucks to set up a membership and 20 bucks per hour for using it, thereabouts.
f(100) = 10 + 20(100) => f(100) = 2010.
f(100), the cost of renting the bike for 100 hours.
Answer: 17 easy how could you not get it but yea thats that
Step-by-step explanation:
Answer:
a = 16
w = 125
x = 120
y = 55
Step-by-step explanation:
<u>FINDING 'a'</u>
31 = a + 46 / 2
62 = a + 46
16 = a
<u>FINDING 'w'</u>
* This section looks Non-Isosceles trapezoid so I will be following the rule according it
w + 55 = 180
w = 125
<u>FINDING 'y'</u>
y = 55
- Because of corresponding angles
<u>FINDING 'x'</u>
* In this case it looks like we are still dealing w/ an non-isosceles trapezoid.
x + 60 = 180
x = 120
Hope this helped ^^
(Please inform me of any mistakes or misunderstandings!)
1000*(1.06)^8. I'm lazy and don't want to type this into a calculator, but what you get out is the answer.
Answer:
3/2 or 1 1/2
Step-by-step explanation:
