Can someone give me the answer

Mathematics

1 answer:

EleoNora [17]2 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

A sleep time of 15.9 hours per day for a newborn baby is at the 10h percentile of the distribution of sleep times for all newbor

Step2247 [10]

The mean time in hours per day for newborn babies is 16.5 hours ⇒ D

Step-by-step explanation:

A sleep time of 15.9 hours per day for a newborn baby is at the 10th

percentile of the distribution of sleep times for all newborn babies

Assuming the distribution is normal with a standard deviation of

0.5 hour

To find the mean time let us do that

1. Use the normal distribution table to find the corresponding z-score

for 10th percentile

2. Use the rule μ = x - zσ, where μ is the mean, σ is the standard

deviation and x is the score

3. Substitute the values of x, σ and z in the rule to find μ

Look to the normal distribution table to find z-score that equivalent

to the area = 10/100 = 0.1 (10th percentile)

∵ z-score = -1.28

∵ σ = 0.5 hour

∵ x = 15.9

∵ μ = x - zσ

- Substitute the values in the rule

∴ μ = 15.9 - (-1.28)(0.5)

∴ μ = 15.9 + 0.64

∴ μ = 16.54 ≅ 16.5 hours

The mean time in hours per day for newborn babies is 16.5 hours

Learn more:

You can learn more about the normal distribution curve in brainly.com/question/8799684

#LearnwithBrainly

6 0

2 years ago

What are the coefficient(s) in the expression 6y+3x-2

Maslowich

Answer:

6 and 3

Step-by-step explanation:

3 0

2 years ago

Hey how do you get from standard form to vertex form?

vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be $\mathbf{ax^{2}+bx+c=0}$ where x is the variable.

Completing the square method is as follows:

send the constant term to other side of equal $\mathbf{ax^{2}+bx=-c}$
divide the whole equation be coefficient of $\mathbf{x^{2}}$ , this will give $\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}$
add $\mathbf{(\frac{b}{2a})^{2}}$ to both side of equality $\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}$
Make one fraction on the right side and compress the expression on the left side $\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}$
rearrange the terms will give the vertex form of standard quadratic equation $\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}$