A colony of flowers is pollinated by hummingbirds and sunbirds. Let H represents the number of hummingbirds and S represent the number of sunbirds that must pollinate the colony so it can survive until next year.

6H+ 4S> 74

This year, 8 hummingbirds pollinated the colony. What is the least number of sun birds that must pollinate the colony to ensure that it will survive until next year?

Answer:

The least number of sun birds is 7

Solution:

Given inequality is:

6H + 4S > 74

Where,

H is the number of hummingbirds

S is the number of sunbirds

This year, 8 hummingbirds pollinated the colony

Substitute H = 8 in given inequality

6(8) + 4S > 74

48 + 4S > 74

Subtract 48 from both sides

48 + 4S - 48 > 74 - 48

4S > 26

Divide both sides by 4

S > 6.5

Hence the least number of sun birds is 7

7 0

3 years ago

Shaun had a collection of 840 matchbox vehicles. Of these vehicles, 15% are four-wheelers and 30% are convertibles. The rest are

lakkis [162]

Answer:

Step-by-step explanation:

15% of 840 is 126

30% of 840 is 252

252

+ 126

378

840 - 378 = 462

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55% of 840 is...

462

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Hope this helps! <3

5 0

3 years ago

Read 2 more answers

Divide: -20.48 ----------- -4

marysya [2.9K]

If the question was -20.48 divided by -4 then the answer is 5.12

3 0

4 years ago