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White raven [17]
3 years ago
6

What is the circumference of this circle r = 2 km

Mathematics
2 answers:
zlopas [31]3 years ago
5 0

Answer: 4*pi, or 12.57 rounded to the nearest hundredth.

Step-by-step explanation: Circumference= pi*diameter. Diameter=2*radius. Radius=2, so diameter=4. 4*pi=12.57

VikaD [51]3 years ago
4 0
Circumference = 12.57km
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The correct triangle is right
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2 years ago
Michael puts 3 beads next to each other
mihalych1998 [28]
When we multiply a whole number with a fraction, we can think of the whole numbers as "over one"...

5 3 5 15
3 * --- = --- * ---- = ----
6 1 6 6

We can further simplify the fraction, by dividing numerator and denominator by 3...

15 15 / 3 5
--- = ------- = ----
6 6 / 3 2

Since this is an improper fraction, we need to turn it into a mixed number...

5 2 + 2 + 1 2 2 1 1 1
---- = -------------- = --- + ---- + --- = 1 + 1 + ---- = 2 --- or 2.5
2 2 2 2 2 2 2
6 0
3 years ago
Please help me! I'm spending 50 points on this question and my last two questions never even got answered!
Verdich [7]

Answer:

C.

Step-by-step explanation:

Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.

So, if we're taking f/g, we have:

\frac{3x^2 + x^4 + 2}{4x - 3}

4x - 3 makes up our denominator, the bottom part of the fraction. So

4x - 3 = 0

4x = 3

x = 3/4

So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.

(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:

\frac{x^2 - 4}{x-2}

If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)

8 0
3 years ago
Finding the roots (zeros)
GenaCL600 [577]

Answer:

1.5 + 1.3228756555323i

1.5 - 1.3228756555323i

Step-by-step explanation:

y = ax^2 + bx + c

a = 1, b = -3, c = 4

Using the quadractic formula:

\frac{-b±\sqrt{b^2-4ac} }{2a} \\\\= \frac{3±\sqrt{9-4(1)(4)}}{2(1)}\\\\= \frac{3±2.64i}{2}\\\\= 1.5 ±  1.32

Note: Kindly ignore the A in the above solution ^

Hence, there is no real solution. It has complex roots.

<em>Feel free to mark this as brainliest! :D</em>

4 0
2 years ago
HELP!!! PLEAAAAAAAAAAAAAAAAAAAASE
Nataly_w [17]
The first answer in the choices
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Read 2 more answers
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