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3 years ago

Find the value of x pls help

Mathematics

1 answer:

Serggg [28]3 years ago

5 0

The value of x is 21.

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Simplify 6(x + y) + (x - y). 6x 7x 7x + 6y 7x + 5y

poizon [28]

6(x + y) + (x - y)

<em>use distributive property</em>

= 6x + 6y + x - y

<em>combine like terms</em>

= (6x + x) + (6y - y)

8 0

3 years ago

Read 2 more answers

If (a, –5) is a solution to the equation 3a = –2b – 7, what is a?

Llana [10]

Answer:

d) 1⃣

Step-by-step explanation:

Multiply -5 by -2 to get , then deduct 7 to get 3. So, you now know that 3 = 3a; 1 = a.

7 0

3 years ago

HELP PLZ (30 POINTS)

jenyasd209 [6]

Answer: I think 1 or 2

5 0

3 years ago

Read 2 more answers

Please help, and thank you!

lawyer [7]

Answer:

3. C

4. D

Step-by-step explanation:

$x^2+25=0\\x^2=-25\\x=\pm\sqrt{-25}$

Once $\sqrt{-1}=i$

$x=\pm5i$

A quadratic equation has no real roots when the discriminant ( $\Delta$ ) is negative. $\Delta$ .

Let's try all the equations:

(A)

$2x^2-7x-9=0\\\\\Delta=\sqrt{\left(-7\right)^2-4\cdot \:2\left(-9\right)}\\\Delta=\sqrt{\left(-7\right)^2+4\cdot \:2\cdot \:9}\\\Delta=\sqrt{121} \\\Delta=11$

(B)

$2x^2=7x\\2x^2-7x=0\\x(2x-7)=0\\x=0\\\text{or}\\2x-7=0\\2x=7\\\\$

$x=\frac{7}{2}$

(C)

$2x^2+7x-9=0\\\Delta = \sqrt{7^2-4\cdot \:2\left(-9\right)}\\\Delta = \sqrt{7^2+4\cdot \:2\cdot \:9}\\\Delta = \sqrt{121} \\\Delta= 11$

(D)

$2x^2-7x+9=0\\\Delta = \sqrt{\left(-7\right)^2-4\cdot \:2\cdot \:9}\\\\\Delta=\sqrt{-23} \\\Delta=\sqrt{23i}$

8 0

3 years ago

The owner of a computer repair shop has determined that their dailyrevenue has mean $7200 and standard deviation $1200. The dail

meriva

Answer:

The required probability is 0.0855

Step-by-step explanation:

Consider the provided information.

The daily revenue has mean $7200 and standard deviation $1200.

$\mu_{\bar x}=7200$

$\sigma=1200$

The daily revenue totals for the next 30 days will be monitored.

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

$\sigma_{\bar x}=\frac{1200}{\sqrt{30}}=219.089$

As we know $Z=\frac{\bar x-\mu_{\bar x}}{\sigma_{\bar x}}$

Substitute $\bar x=7500, \mu_{\bar x}=7200\ and\ \sigma_{\bar x}=219.089$ in above formula.

$Z=\frac{7500-7200}{219.089}=1.3693$

From the standard normal table P( Z >1.3693) = 0.0855

Hence, the required probability is 0.0855

7 0

3 years ago