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Goshia [24]
3 years ago
5

Rachel reads 1/5 of the pages of a book plus 12 pages on the first day.

Mathematics
2 answers:
kkurt [141]3 years ago
6 0

Answer:

Let's say that the whole book have 5a pages.

First day: a + 12

Second day: (4a)1/4+15= a + 15

Third day: (1/3)[ 4a - (a+15)] +18= a + 13

Forth day: 70

So we get this:

(a + 12) + (a + 15) + (a + 13) + 70 = 5a

a + 12 + a + 15 + a + 13 + 70 = 5a

3a + 110 = 5a

3a - 5a = -110

-2a = -110

a = 55

5a = 5(55) = 275

So the total pages are in the book is:

275 pages

GenaCL600 [577]3 years ago
5 0
1. Add the first two fractions together, 1/5 + 1/4 + 1/3 = 4/2

2. Then add 12 + 15 + 18 = 45

3. Then add 70 + 45 = 115

The answer to this question is 115 total pages in the book. I hope this helped. Comment on this if u have any further questions or concerns.

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monitta
Hello There!

Percentage increase or decrease = difference of values / original value.  x 100
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In short, the decrease in Athena's daily water consumption is 5%.

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Consider the sequence of numbers: 3/8, 3/4, 1 /18, 1 1/2, 1 7/8
vredina [299]

Question:

Consider the sequence of numbers: \frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}

Which statement is a description of the sequence?

(A) The sequence is recursive, where each term is 1/4 greater than its preceding term.

(B) The sequence is recursive and can be represented by the function

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(C) The sequence is arithmetic, where each pair of terms has a constant difference of 3/4 .

(D) The sequence is arithmetic and can be represented by the function

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Answer:

Option B:

The sequence is recursive and can be represented by the function

f(n + 1) = f(n) + \frac{3}{8}  .

Explanation:

A sequence of numbers are

\frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}

Let us first change mixed fraction into improper fraction.

\frac{3}{8}, \frac{3}{4}, \frac{9}{8}, \frac{3}{2}, \frac{15}{8}

To find the pattern of the sequence.

To find the common difference between the sequence of numbers.

\frac{3}{4}-\frac{3}{8}=\frac{6}{8}-\frac{3}{8}= \frac{3}{8}

\frac{9}{8}-\frac{3}{4}=\frac{9}{8}-\frac{6}{8}= \frac{3}{8}

\frac{3}{2}-\frac{9}{8}=\frac{12}{8}-\frac{9}{8}= \frac{3}{8}

\frac{15}{8}-\frac{3}{2}=\frac{15}{8}-\frac{12}{8}= \frac{3}{8}

Therefore, the common difference of the sequence is 3.

That means each term is obtained by adding \frac{3}{8} to the previous term.

Hence, the sequence is recursive and can be represented by the function f(n + 1) = f(n) + \frac{3}{8}  .

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