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Vladimir79 [104]
3 years ago
8

Help please I need it as soon as possible ​

Mathematics
1 answer:
MAVERICK [17]3 years ago
3 0

Answer:

y=1/2+3

Step-by-step explanation:

For the first one, 0 and 3. 0/2 is not possible so we just add 3.

Second, 1/2 is 0.5 of 1/2. Plus 3 is 3 1/2.

Third, 2/2 = 1 + 3 = 4.

And last, 3/2 = 1.5 or 1 1/2. 1 1/2 + 3 is 4 1/2

--

Hope this helps!

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If wallpaper costs $1.25 per squared foot, how much will it cost to put mew wallpaper in a room with area dimensions of 17 ft lo
AleksandrR [38]

The area of the room is :

\begin{gathered} A=17\cdot16 \\ A=272 \end{gathered}

and if the cost is 1.25 per square foot then the total cost will be:

272\cdot1.25=340

is $340 dollars

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1 year ago
Tony's Mom gives him a weekly allowance. Due to his bad behavior, his allowance has been shrinking at a rate of 2 3/10 dollars e
nikitadnepr [17]

Answer:

-3 2/7 per day

Step-by-step explanation:

-2 3/10 then put that all over 3 1/2

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3 years ago
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A rectangle has an area of 24 cm2 Function f gives the length of the rectangle, in centimeters, when the width is w cm. Determin
levacccp [35]

Answer:

Input is the value of w and the function f = 24/w as length x breadth = area of rectangle

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If w = 48, then f = 24/48 = 0.5cm. So, it is a possible input of the function.

If w = 0, then f = 24/0 = 0cm. So, it is not a possible input of the function as it cannot be defined

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vovikov84 [41]

Answer:

The number of key rings sold on a particular day when the total profit is $5,000 is 4,000 rings.

Step-by-step explanation:

The question is incomplete.

<em>An owner of a key rings manufacturing company found that the profit earned (in thousands of dollars) per day by selling n number of key rings is given by </em>

<em />P=n^2-2n-3<em />

<em>where n is the number of key rings in thousands.</em>

<em>Find the number of key rings sold on a particular day when the total profit is $5,000.</em>

<em />

We have the profit defined by a quadratic function.

We have to calculate n, for which the profit is $5,000.

P=n^2-2n-3=5\\\\n^2-2n-8=0

We have to calculate the roots of the polynomial we use the quadratic equation:

n=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\n= \frac{-2\pm\sqrt{4-4*1*(-8)}}{2}= \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{36}}{2} =\frac{-2\pm6}{2} \\\\n_1=(-2-6)/2=-8/2=-4\\\\n_2=(-2+6)/2=4/2=2

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