Answer:
D
Step-by-step explanation:
We are given that:

And we want to find the value of tan(2<em>x</em>).
Note that since <em>x</em> is between π/2 and π, it is in QII.
In QII, cosine and tangent are negative and only sine is positive.
We can rewrite our expression as:

Using double angle identities:

Since cosine relates the ratio of the adjacent side to the hypotenuse and we are given that cos(<em>x</em>) = -1/3, this means that our adjacent side is one and our hypotenuse is three (we can ignore the negative). Using this information, find the opposite side:

So, our adjacent side is 1, our opposite side is 2√2, and our hypotenuse is 3.
From the above information, substitute in appropriate values. And since <em>x</em> is in QII, cosine and tangent will be negative while sine will be positive. Hence:
<h2>

</h2>
Simplify:

Evaluate:

The final answer is positive, so we can eliminate A and B.
We can simplify D to:

So, our answer is D.
Step-by-step explanation:
2A=h(a+b)
2A=ha+hb
2A-hb=ha
2A-hb/h=a
The answer is 7/8. 28/4 = 7, 32/4=8.
Observe the given data distribution table carefully.
The 5th class interval is given as,

The upper limit (UL) and lower limit (LL) of this interval are,

Thus, the upper-class limit of this 5th class is 17.4.
The slope of a line with those points is 1/6m. To find a perpendicular slope find the reciprocal of the slope of the first line. The slope is 6m.
Have a great day, brainliest would be fantastic