<h3>Unit price is $ 0.56 per pound of potatoes</h3><h3>Unit price is $ 3.1 per pound of broccoli</h3>
<em><u>Solution:</u></em>
Given that,
Unit price is the price of 1 unit
<h3><u>Find unit price of potatoes</u></h3>
A shopper paid $2.52 for 4.5 pounds of potatoes
Thus unit price is $ 0.56 per pound of potatoes
<h3><u>Find unit price of broccoli</u></h3>
$7.75 for 2.5 pounds of broccoli
Thus unit price is $ 3.1 per pound of broccoli
Step 1. Set up long division
_______
7| 1 9 8 6
Step 2. <span>Calculate 19 ÷ 7, which is 2 with a remainder of 5.
2
</span> _______
7| 1 9 8 6
1 4
_________
5
Step 3. Bring down 8, so that 58 is large enough to be divided by 7.
2
_______
7| 1 9 8 6
1 4
_________
5 8
Step 4. <span>Calculate 58 ÷ 7, which is 8 with a remainder of 2.
</span> 2 8
_______
7| 1 9 8 6
1 4
_________
5 8
5 6
_________
2
Step 5. <span>Bring down 6, so that 26 is large enough to be divided by 7.
</span> 2 8
_______
7| 1 9 8 6
1 4
_________
5 8
5 6
_______
2 6
Step 6. Calculate 26 ÷ 7, which is 3 with a remainder of 5.
2 8 3
_______
7| 1 9 8 6
1 4
_________
5 8
5 6
_______
2 6
2 1
______
5
Step 7. <span>Therefore, 1986 ÷ 7 = 283 with a remainder of 5.
823 With a remainder of 5
Done!
</span><span>Decimal Form If Needed: 283.714286</span>
Answer:
P = 0.5Q - 20
Step-by-step explanation:
P = kQ + c
substitute Q = 60 , P = 10 into the equation
10 = 60k + c → (1)
substitute Q = 240, P = 100 into the equation
100 = 240k + c → (2)
subtract (1) from (2) term by term to eliminate c
90 = 180k ( divide both sides by 180 )
= 
= 0.5 = k
substitute k = 0.5 into (1) and solve for c
10 = 60(0.5) + c
10 = 30 + c ( subtract 30 from both sides )
- 20 = c
then
P = 0.5Q - 20
Step-by-step explanation:
zero ...................
