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3 years ago

Pls help, will give brainliest

Mathematics

2 answers:

Zinaida [17]3 years ago

8 0

Answer:

Acute Triangle :))

Ivahew [28]3 years ago

5 0

It’s acute triangle ma :)

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Based on the graphic, which three-dimensional figure has the greatest volume?

dedylja [7]

Answer:c) they have the same volume

Step-by-step explanation: same height equals same volume

5 0

3 years ago

Please help me with this math question!

Alenkinab [10]

The bases are both 2, so we would subtract the exponents. This is because the rule is

(a^b)/(a^c) = a^(b-c)

In this case,
a = 2
b = 3/4
c = 1/2

So this means
b - c = (3/4) - (1/2) = (3/4) - (2/4) = 1/4

After subtracting the exponents, the final exponent is 1/4

So the expression simplifies to 2^(1/4) which is the same as $\sqrt[4]{2}$ (fourth root of 2)

4 0

3 years ago

Can someone help me Write an equation for this graph?

Paladinen [302]

Y=2/3x-1 is the equation:)

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3 years ago

Solve the inequality<br> 3 + 9x >4(x+7)<br> pls help

alexandr402 [8]

Answer:

x<5

Step-by-step explanation:

the greater sign will firstly be changed to = for better solving so we obtain

3+9x=4(x+7)by opening bracket

3+9x=4x+28

9x-4x=28-3

5x=25

divide all through by 5x

we obtain

x=5

the greater sign change here

which is x<5

8 0

3 years ago

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

8 0

3 years ago