Answer:
341.46miles
Explanation:
Find the diagram attachment.
To get the displacement D, we will use the cosine rule as shown;
D² = 200²+150²-2(160)(400)cos65°
D² = 40000+22500-128000cos65°
D² = 62500+54095.14
D² = 116595.14
D = √116595.14
D= 341.46 miles
Hence the plane final displacement is 341.46miles
Answer:
a) -1.325 μC
b) 4.17μC
Explanation:
First, you need to know that charge is conserved. So, the adition of the charges, as there is no lost in charge, should always be the same. Also, after the wire is removed, both spheres will have the same charge, trying to find equilibrium. In summary:
We know both q1f and q2f must be positive, because the negative charge at the beginning was the the smaller.
The electrostatic force is equal to:
K is the Coulomb constant, equal to 9*10^9 Nm^2/C^2
Now, we are told that the electrostatic force after the wire is equal to 0.0443 N:
Originally, the force is negative because it was an attraction force, therefore, its direction was opposite to the direction of the repulsive force after the wire:
Solving the quadratic equation:
for this values q_1 wil be:
So as you can see, the negative charge will always be -1.325 μC and the positive 4.17μC
Answer:
The answer is 3213.6 grams.
Explanation:
In meters the room dimensions are 3.05-3.2-6.86.
Total volume of the room is:
66.95 m3.
The density of carbon monoxide is 48 g/m3. Then total grams is present in a room measuring:
Answer:
The minimum heat required is 171626 joules.
Explanation:
By First Law of Thermodynamics, the amount of heat (), in joules, is equal to the change in internal energy of water. The minimum heat required is the sensible heat necessary to heat up the water. That is:
(1)
Where:
- Density of water, in kilograms per cubic meter.
- Volume of water, in cubic meters.
- Specific heat of water, in joules per kilogram-degree Celsius.
- Change in temperature, in degrees Celsius.
If we know that ,
,
and
, then the minimum heat required is:
The minimum heat required is 171626 joules.