I believe the answer is 'A'
The solute would then sink to the bottom and would not dissolve
Answer:
a)At the mean position
b)At the extremes positions
Explanation:
Given that mass is having oscillation motion.
We know that
1. At the mean position -The velocity of the mass is maximum and the acceleration of the mass is minimum.The net force on the mass will be zero.
2. At the extreme position-The velocity of the mass is minimum and the acceleration of the mass is maximum.The net force on the mass will not be zero.
Therefore
a)At the mean position
b)At the extremes positions
Answer:
Explanation:
The change in momentum of the ball is equal to the impulse exerted on it, therefore:
where
is the change in momentum
F is the average force exerted on the ball
is the time during which the force is applied
In this problem,
F = 156 N
So, the change in momentum of the ball is
Answer:
Explanation:
Given a mass spring system
At t = 0.1s, the positions is at x=8cm
x(0.1) = 8cm = 0.08m
Spring constant k=16N/m
Mass attached m = 4kg
Amplitude of oscialltion A=10cm = 0.1m
The angular frequency can be calculated using
w = √k/m
Where k is spring constant in N/m
m is mass attached object to the spring in kg
w = √16/4 = √4
w = 2rad/s.
Generally, the equation of a spring is given as
x = ACos(wt+Φ)
Where,
A is amplitude in metre
w is angular frequency in rad/sec
Φ is phase in radian
x(t) = 0.1Cos(2t + Φ)
At t=0.1 x = 0.08
0.08 = 0.1Cos(0.2+Φ)
Cos(0.2+Φ) = 0.08/0.1
Cos(0.2+Φ) = 0.8
0.2+Φ = ArcCos(0.8), note angle in radiant
0.2+Φ = 0.644
Φ = 0.644 — 0.2
Φ = 0.444 rad.
The phase of the SHM is 0.444rad
The answer is E = 0.44 rad