A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9
B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6
C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16
D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25
The answer is D.
Answer:
The height of the another cylinder 'h' = 7
Step-by-step explanation:
<u>Explanation</u>:-
<u>Step 1:-</u>
Surface area of the cylinder = 2пrh + 2пr^2
Given radius of first cylinder is 20cm
given height of the first cylinder is 2 cm
The surface area of first cylinder is = 2пrh + 2пr^2
= 2п(20)(2)+2п(2)^2
= 4п(20+2)
The surface area of first cylinder is 88п
<u>Step 2</u>:
given data The surface area of first cylinder is 88п is same as second cylinder also
<u>Find the height of the second cylinder</u>
Given Radius of the second cylinder r = 4
Surface area of the cylinder = 2пrh + 2пr^2 = 88п
2п(4)h+2п(4)^2 =88п
on simplification we get
2п (4h+16) = 88п
after cancellation '2п' value and on simplification, we get
4h+16 = 44
4h = 44-16
4h = 28
h=7
Therefore the height of the another cylinder is 'h' =7
Divide 296 by 16 you get 18.5 then add the 5.75 to get 24.25
So the answer is 24.25
That'd be y = 70* (1-.00043)^t, where the rate of decrease is really 0.43% and t denotes the # of weeks.
This simplifies to y = 70*(0.00057)^t.
Oh its super easy! 5w = 5 x W, so take one of the numbers like 2 and times it by 5 and add it to the rest of the problem, and see if the number you get is in your answers, if its not, then try the others!
