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sergij07 [2.7K]
3 years ago
13

What is the solution to 5p - 20 = 35

Mathematics
2 answers:
tester [92]3 years ago
8 0
P = 11

Add 20 to both sides to get 5p = 55.

Then divide by 5 to get 'p' by itself.

55 / 5 = 11.

Sergio039 [100]3 years ago
5 0
Our current equation is:
5p - 20 = 35.
To solve for P, we need to get 5P by itself and then simplify if possible.
5p is not by itself yet.
Add 20 to both sides.
5p = 55.
Now to solve for p, since 5 is being multiplied by p, we need to do the opposite.
Divide both sides by 5.
p = 11 is your solution.
I hope this helps!
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s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{5}(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}\cdot [(0.53-(0.502))^2+...+(0.37-(0.502))^2]}\\\\\\s=\sqrt{\dfrac{1}{4}\cdot [(0.001)+(0.022)+(0.002)+(0)+(0.017)]}\\\\\\            s=\sqrt{\dfrac{0.04188}{4}}=\sqrt{0.01047}\\\\\\s=0.102

The 10% of the advertised content is:

0.10\cdot 6.0\;oz=0.6\:oz

Hypothesis test for the population mean:

The claim is that the remaining toothpaste is significantly is less than 10% of the advertised net content.

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H_0: \mu=0.6\\\\H_a:\mu< 0.6

The significance level is 0.05.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.102}{\sqrt{5}}=0.046

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{0.502-0.6}{0.046}=\dfrac{-0.098}{0.046}=-2.148

The degrees of freedom for this sample size are:

df=n-1=5-1=4

This test is a left-tailed test, with 4 degrees of freedom and t=-2.148, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.049) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the remaining toothpaste is significantly is less than 10% of the advertised net content.

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5 0
3 years ago
Read 2 more answers
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