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Leno4ka [110]
3 years ago
6

HELP I NEED HELP ASAP

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
7 0

Answer:

Option C is the correct answer

Step-by-step explanation:

C. Multiply both sides of the equation by 20

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DBJ + ABJ = 90 DBJ = ABC DBC + ABC = 90 JBC + DBC + ABJ = 90 And last but not least: ABJ = 28
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4 years ago
A stack of cards is numbered 1 to 21. Kelly pulls one card from the stack. What is the best approximation for the probability th
ASHA 777 [7]
The correct answer is 48%

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10 / 21 x 100 = 48%
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FInd the slope and y-intercept of the line
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5 0
3 years ago
What is the area of a pizza with a diameter of 12 inches? Round to the nearest tenth. Use 3.14 for pi.
Flauer [41]

Answer:

\boxed {\boxed {\sf a \approx 113.0 \ in^2}}

Step-by-step explanation:

Assuming this pizza is a circle, we can use this formula for area:

a= \pi r^2

1. Find Radius

We are given the diameter: 12 inches, but the formula uses radius.

The radius is half the diameter, or:

r=\frac{d}{2}

r=\frac{12 \ in}{2}

r= 6 \ in

2. Calculate Area

Substitute the radius (6 inches) in for r. The question also asks us to use 3.14 for pi.

a= (3.14)(6 \ in)^2

Solve the exponent.

  • (6 in)²= 6 in* 6 in= 36 in²

a= (3.14)(36 \ in^2)

Multiply.

a= 113.04 \ in^2

3. Round

The question asks us to round to the nearest tenth.

The 4 in the hundredth place tells us to leave the 0 in the tenth place.

a \approx 113.0 \ in^2

The area of the pizza is about 113.0 square inches.

7 0
3 years ago
A random sample of 500 of these people is drawn, of whom 194 turn out to be currently enrolled in college. Estimate the percenta
Rzqust [24]

Answer:

0.388 - 2.00\sqrt{\frac{0.388(1-0.388)}{500}}=0.344

0.388 + 2.00\sqrt{\frac{0.388(1-0.388)}{500}}=0.432

The 95.5% confidence interval would be given by (0.344;0.432)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The estimated proportion on this case is given by:

p = \frac{X}{n}= \frac{194}{500}=0.388

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95.5% of confidence, our significance level would be given by \alpha=1-0.955=0.045 and \alpha/2 =0.0225. And the critical value would be given by:

z_{\alpha/2}=-2.00, z_{1-\alpha/2}=2.00

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.388 - 2.00\sqrt{\frac{0.388(1-0.388)}{500}}=0.344

0.388 + 2.00\sqrt{\frac{0.388(1-0.388)}{500}}=0.432

The 95.5% confidence interval would be given by (0.344;0.432)

4 0
3 years ago
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