Answer: x = 4, y = 3
<u>Step-by-step explanation:</u>
and ![y=x-1](https://tex.z-dn.net/?f=y%3Dx-1)
Using substitution method we get:
![x-1=\dfrac{1}{4}x+2\\\\\text{subtract}\ \dfrac{1}{4}x\ \text{from both sides}\rightarrow \dfrac{3}{4}x-1=2\\\\\text{add 1 to both sides}\rightarrow \dfrac{3}{4}x=3\\\\\text{multiply both sides by 4}\rightarrow 3x=12\\\\\text{divide both sides by 3}\rightarrow x=4\\\\\text{Insert x = 4 into one of the original equations to solve for y:}\\y=x-1\\y =(4)-1\\y=3](https://tex.z-dn.net/?f=x-1%3D%5Cdfrac%7B1%7D%7B4%7Dx%2B2%5C%5C%5C%5C%5Ctext%7Bsubtract%7D%5C%20%5Cdfrac%7B1%7D%7B4%7Dx%5C%20%5Ctext%7Bfrom%20both%20sides%7D%5Crightarrow%20%5Cdfrac%7B3%7D%7B4%7Dx-1%3D2%5C%5C%5C%5C%5Ctext%7Badd%201%20to%20both%20sides%7D%5Crightarrow%20%5Cdfrac%7B3%7D%7B4%7Dx%3D3%5C%5C%5C%5C%5Ctext%7Bmultiply%20both%20sides%20by%204%7D%5Crightarrow%203x%3D12%5C%5C%5C%5C%5Ctext%7Bdivide%20both%20sides%20by%203%7D%5Crightarrow%20x%3D4%5C%5C%5C%5C%5Ctext%7BInsert%20x%20%3D%204%20into%20one%20of%20the%20original%20equations%20to%20solve%20for%20y%3A%7D%5C%5Cy%3Dx-1%5C%5Cy%20%3D%284%29-1%5C%5Cy%3D3)
Well 3 4/4 is equal to 4. But if you want to find the mixed number...
3 4/4 is equal to 16/4
3 4/4 is also equal to 3 2/2 or 3 8/8. The number in the end just has to equal the whole number 4.
Hope this helps!:)
Answer:
13+2h
Step-by-step explanation:
the sum of 13 (13+) and twice a number h (13+2h)
3a^2 - 14(a) - 24
3a^2 + (-18a+4a) - 24
3a^2 - 18a + 4a - 24
(3a^2-18a) + (4a - 24)
3a (a - 6) + 4 (a - 6)
Answer is (a -6) (3a + 4)