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3 years ago

Identify the lateral area and surface area of a regular triangular pyramid with base edge length 14 cm and slant height 15 cm

Mathematics

2 answers:

Nata [24]3 years ago

7 0

Answer would be D L=315 cm2 ; S=399 cm2

posledela3 years ago

6 0

Answer:

D) L = 315 cm2 ; S = 399.9 cm2

Step-by-step explanation:

Lateral area;

3 × (½)(14)(15)

315 cm²

Surface area:

315 + (½)(14)(14)sin(60)

399.8704896 cm²

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5. How much should Chantal budget per month to make sure she has enough

solmaris [256]

Answer:

$525.13

Step-by-step explanation:

cost per month = total expenses / months in a year

total expenses = fixed cost + variable cost

$2,125.10 + $4,176.43 = $6,301.53

cost per month = $6,301.53/ 12 = $525.13

4 0

2 years ago

Complete the steps to evaluate the following expression, given log3a = −0.631.

Zielflug [23.3K]

$\log _{3}(3)=1$ and $\log _{3} \frac{a}{3}=-1.631$

Solution:

Given value $\log _{3} a=-0.631$ .

To evaluate the expression $\log _{3} \frac{a}{3}$ .

Using logarithmic rule: $\log _{b}\left(\frac{M}{N}\right)=\log _{b}(M)-\log _{b}(N)$

$$\log _{3} \frac{a}{3}=\log _{3}(a)-\log _{3}(3)$

We know that $\log _{3} a=-0.631$ .

$$\log _{3} \frac{a}{3}=-0.631-\log _{3}(3)$

Using another logarithmic rule: $\log _{b} b=1$

$$\log _{3} \frac{a}{3}=-0.631-1$

$$\log _{3} \frac{a}{3}=-1.631$

Hence $\log _{3}(3)=1$ and $\log _{3} \frac{a}{3}=-1.631$ .

6 0

2 years ago

Read 2 more answers

Find the equation of the line. Use exact numbers.

kvasek [131]

Answer:

y=-3/2x+3

Good luck:)

5 0

2 years ago

Please help: 12x^4(-5/6x^3y^2) If possible, include steps Thanks.

tangare [24]

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Question
---------------------------------------------------------------------------------------
$12x^4(- \frac{5}{6} x^3y^2)$

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Multiply the constant: 12 x (-5/6)
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$-10x^4( x^3y^2)$

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Multiply the x (we add the power together when we multiply)
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$-10x^7y^2$

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Answer: -10x⁷y²
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4 0

2 years ago

The capacity of the milk pitcher on the counter is 9/10 liter each one pitcher has3/8 of milk in it and the other pitcher has 5/

KatRina [158]

Answer:

57/80L

Step-by-step explanation:

Given that the capacity (i.e maximum possible volume) of a pitcher is 9/10L

1st Pitcher is 3/8 full of milk

Hence Vol of milk in 1st pitcher = 9/10 x 3/8 = 27/80L

2nd Pitcher is 5/12 full of milk

Hence Vol of milk in 2nd pitcher = 9/10 x 5/12 = 3/8 = 30/80L

Total volume = 27/80 + 30/80 = 57/80L

4 0

2 years ago