All categories

2 years ago

9,-7 with a translation of (x-8,y)

Mathematics

2 answers:

ryzh [129]2 years ago

7 0

Answer:

The last part is not there

Step-by-step explanation:

Dimas [21]2 years ago

5 0

The answer is c I think

You might be interested in

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

The table shows how many of each type of movie are being shown at a theater.

alexira [117]

Answer:

ratio is 5isto 4 byan action and drama

7 0

3 years ago

HELP<br> Find the area of the polygon with the vertices of A(2,2), B(2,7), C(8,7),and D(4,2)

Illusion [34]

I think it would be 36 it’s what my friend told me I’m not sure though sorry if it’s wrong.

8 0

3 years ago

Complete. Express the product in simplest form.<br><br> 2/5 of 7/10 =

tester [92]

Of means multiply in math (most of the time).
So multiply.
2/5 x 7/10 = 14/50 divided by 2/2 = 7/25

3 0

3 years ago

Read 2 more answers

Which of the following figures has a circumference that is closest to 121 inches?

Eduardwww [97]

Answer:

a circle with a diameter of 19.3 inches

3 0

2 years ago

9,-7 with a translation of (x-8,y)￼￼

9,-7 with a translation of (x-8,y)