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Luden [163]
3 years ago
7

Find the exact length of the third side

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
4 0

Answer:

The third side =4

Step-by-step explanation:

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Which solid has six faces, four lateral faces, two bases, eight vertices, and 12 edges?
Licemer1 [7]

Answer:

Rectangular prism

Step-by-step explanation:

The solid that has six faces, four lateral faces, two bases, eight vertices, and 12 edges is the <em>rectangular</em><em> </em><em>prism</em>

<em>SINCE</em><em> </em><em>IT'S</em><em> </em><em>CORRECT</em><em>,</em><em> </em><em>PLEASE</em><em> </em><em>DO MARK</em><em> </em><em>ME AS</em><em> </em><em>BRAINLIEST UWU</em><em> </em>

7 0
3 years ago
The model represents an equation. What value of x makes the equation true?
Slav-nsk [51]

Answer:

A) 29/8

Step-by-step explanation:

On the left side of the equals sign, we have five x's and nine -1's.

On the right side of the equals sign, we have three -x's and twenty 1's.

Both sides are equal, so:

5(x) + 9(-1) = 3(-x) + 20(1)

5x − 9 = -3x + 20

Add 3x to both sides.

8x − 9 = 20

Add 9 to both sides.

8x = 29

Divide both sides by 8.

x = 29/8

5 0
3 years ago
Please help me!!!!!​ i need full answer.
salantis [7]

Answer:

see explanation

Step-by-step explanation:

Using the sum/ difference → product formula

cos x - cos y = - 2sin( \frac{x+y}{2})sin (\frac{x-y}{2} )

sin x - sin y = 2cos (\frac{x+y}{2} )sin (\frac{x-y}{2} )

Given

(cosA - cosB)² + (sinA - sinB )²

= [ - 2sin(\frac{A+B}{2})sin(\frac{A-B}{2} ) ]² + [ 2cos(\frac{A+B}{2} )sin(\frac{A-B}{2} ) ]²

= 4sin² (\frac{A+B}{2} )sin² (\frac{A-B}{2} ) + 4cos² (\frac{A+B}{2} )sin² ( \frac{A-B}{2} )

= 4sin² (\frac{A-B}{2} )[ sin² ( \frac{A+B}{2} ) + cos² ( \frac{A+B}{2} ) ← sin²x + cos²x = 1

= 4sin² ( \frac{A-B}{2} ) × 1

= 4sin² ( \frac{A-B}{2} ) = right side ⇒ proven

4 0
3 years ago
Need help on this question. Will give brainliest
Llana [10]

Answer: C

Step-by-step explanation:

Bcuz when its square it results to something known as the perfect square trinomial. Thats the way i learned it. Ion know if u learned it the same way pero i hope this helps.

3 0
2 years ago
In x^a=y, y^b=z, z^c=x, then prove that abc=1​
Marysya12 [62]

Step-by-step explanation:

Let, x^a =y......(1) and

y^b =z.....(2) and

z ^c =x......(3).

Now, using (1) in (2) we get,

x ^ab =z......(4).

Now, using (4) in (3) we get,

x ^abc =x

or, x ^abc =x ^1

or, abc=1.

Hope it will help :)

7 0
2 years ago
Read 2 more answers
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