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3 years ago

Need to solve for x 4x - 2 = 2x + 1

Mathematics

2 answers:

natta225 [31]3 years ago

4 0

Add the 2 to the 1 and then minus 2x from 4x so you get 2x = 3

BlackZzzverrR [31]3 years ago

3 0

The answer would be x= 3/2

You would take 2 and add it to the other side leaving 4x by itself, leaving you with the equation 4x= 2x + 3.
Then you would divide both side by 2 giving you 2x= 3. Then you would divide by 2 again to get x=3/2.

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Write the slope intercept form of the equation of the line through the given points.

Jet001 [13]

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 1}}\quad ,&{{ -2}})\quad 
% (c,d)
&({{ 1}}\quad ,&{{ 3}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{3-(-2)}{1-1}\implies \stackrel{und efined}{\cfrac{3+2}{0}}$

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3 years ago

Solving right triangles

Sav [38]

<h2>1. Answer:</h2>

A right triangles is a triangle having a 90 degree side. According to the figure, the sides of this triangle are expressed in inches. Therefore, we can find the missing sides and angles as follows:

<u>m∠B:</u>

The sum of the three interior angles of any triangle is 180°, therefore:

$m \angle B + 51^{\circ} + 90^{\circ} = 180^{\circ} \\ \\ \boxed{m \angle B = 39^{\circ}}$

We must use the law of sines as follows:

$\frac{CA}{sin39^{\circ}}=\frac{9}{sin51^{\circ}} \\ \\ \therefore CA=\frac{9sin39^{\circ}}{sin51^{\circ}} \\ \\ \therefore \boxed{CA=7.3in}$

$\frac{AB}{sin90^{\circ}}=\frac{9}{sin51^{\circ}} \\ \\ \therefore AB=\frac{9sin90^{\circ}}{sin51^{\circ}} \\ \\ \therefore \boxed{AB=11.6in}$

<h2>2. Answer:</h2>

According to the figure, the sides of this triangle are expressed in meters. Therefore, we can find the missing sides and angles as follows:

<u>m∠A:</u>

The sum of the three interior angles of any triangle is 180°, therefore:

$m \angle A + 53^{\circ} + 90^{\circ} = 180^{\circ} \\ \\ \boxed{m \angle A = 37^{\circ}}$

We must use the law of sines as follows:

$\frac{CA}{sin53^{\circ}}=\frac{5}{sin90^{\circ}} \\ \\ \therefore CA=\frac{5sin53^{\circ}}{sin90^{\circ}} \\ \\ \therefore \boxed{CA=4.0m}$

$\frac{CB}{sin37^{\circ}}=\frac{5}{sin90^{\circ}} \\ \\ \therefore CB=\frac{5sin37^{\circ}}{sin90^{\circ}} \\ \\ \therefore \boxed{CB=3.0m}$

<h2>3. Answer:</h2>

According to the figure, the sides of this triangle are expressed in miles. Therefore, we can find the missing sides and angles as follows:

<u>m∠B:</u>

The sum of the three interior angles of any triangle is 180°, therefore:

$m \angle A + 28^{\circ} + 90^{\circ} = 180^{\circ} \\ \\ \boxed{m \angle B = 62^{\circ}}$

We must use the law of sines as follows:

$\frac{CB}{sin28^{\circ}}=\frac{29.3}{sin62^{\circ}} \\ \\ \therefore CB=\frac{29.3sin28^{\circ}}{sin62^{\circ}} \\ \\ \therefore \boxed{CA=15.6mi}$

$\frac{AB}{sin90^{\circ}}=\frac{29.3}{sin62^{\circ}} \\ \\ \therefore AB=\frac{29.3sin90^{\circ}}{sin62^{\circ}} \\ \\ \therefore \boxed{AB=33.2mi}$

<h2>4. Answer:</h2>

According to the figure, the sides of this triangle are expressed in miles. Therefore, we can find the missing sides and angles as follows:

<u>m∠A:</u>

The sum of the three interior angles of any triangle is 180°, therefore:

$m \angle A + 24^{\circ} + 90^{\circ} = 180^{\circ} \\ \\ \boxed{m \angle A = 66^{\circ}}$

We must use the law of sines as follows:

$\frac{CA}{sin66^{\circ}}=\frac{14}{sin90^{\circ}} \\ \\ \therefore CA=\frac{14sin66^{\circ}}{sin90^{\circ}} \\ \\ \therefore \boxed{CA=12.8mi}$

$\frac{CB}{sin24^{\circ}}=\frac{14}{sin90^{\circ}} \\ \\ \therefore CB=\frac{14sin24^{\circ}}{sin90^{\circ}} \\ \\ \therefore \boxed{CB=5.7mi}$

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3 years ago

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Luden [163]

Answer:

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3 years ago

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Alexxandr [17]

9514 1404 393

Answer:

A, C, F, G, I

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A relation is "odd" if it is symmetrical about the <em>origin</em>. That is, f(-x) = -f(x). Here are the symmetries of the graphs shown:

A: origin

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3 years ago

carl shades a row in the multiplication table, the products in the row are all event, the ones digits in the products repeat 0,4

FinnZ [79.3K]

The <em>correct answer</em> is:

The 4's row.

Explanation:

The even rows in a the multiplication chart are the 2's, 4's, 6's, 8's, 10's, and 12's.

In the 2's row, we have: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24. Looking at the ones digits, we do not have the correct pattern.

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3 years ago

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