<span>3x^2y^2 − 2xy^2 − 8y^2 =
y^2 (3x^2 - 2x - 8) =
factoring with leading coefficient:
for ax2+bx+c find two numbers n,m, that m*n = a*c and m+n = b
</span><span><span>
3x^2 - 2x - 8
a=3, b=-2, c=-8
</span>a*c = 3*(-8) = -24
-24=(-6)*4 and -6+4=-2, so m=-6 and n=4
replace bx with mx + nx and factor by grouping
</span><span>
3x^2 - 2x - 8 = </span>3x^2 -6x + 4x -8 = 3x(x-2) + 4(x-2) = (3x+4)(x-2)
answer:
<span>3x^2y^2 − 2xy^2 − 8y^2 = y^2(3x+4)(x-2)</span>
Answer:
12 units
Step-by-step explanation:
Given that :
R(-3,2)
S(2,2)
T(2,-5).
The total length ;
Distance between two points : √[(x2 - x1)² + (y2 - y1)²]
Distance between R and S :
R = (-3,2)
S(2,2)
√[((2 - (-3))^2 + (2 - 2)^2]
Sqrt(5^2 + 0^2)
D1 = 5 units
Distance between S and T:
S(2,2)
T(2,-5).
D2 = √[(2 - 2)^2 + (-5 - 2)^2]
D2 = sqrt(0^2 + (-7)^2)
D2 = 7 units
Hence, total length = D1 + D2 = (5 + 7) = 12 units
Answer:
562
Step-by-step explanation:
Step-by-step explanation:
please mark me as brainlest
Answer:
Step-by-step explanation:
v=3+1.5x7
v= 13.5 m/s
