Answer:
option b)
tan²θ + 1 = sec²θ
Step-by-step explanation:
The Pythagorean trigonometric identity is a trigonometric identity expressing the Pythagorean theorem in terms of trigonometric functions.
hypotenuse² = height² + base²
Given in the questions are some pythagorus identities which except of b) are all incorrect as explained below.
<h3>1)</h3>
sin²θ + 1 = cos²θ incorrect
<h3>sin²θ + cos²θ = 1 correct</h3><h3 /><h3>2)</h3>
by dividing first identity by cos²θ
sin²θ/cos²θ + cos²θ/cos²θ = 1/cos²θ
<h3>tan²θ + 1 = sec²θ correct</h3><h3 /><h3>3)</h3>
1 - cot²θ = cosec²θ incorrect
by dividing first identity by sin²θ
sin²θ/sin²θ + cos²θ/sin²θ = 1/sin²θ
<h3>1 + cot²θ = cosec²θ correct</h3><h3 /><h3>4)</h3>
1 - cos²θ = tan²θ
not such pythagorus identity exists
Answer:

Step-by-step explanation:
The distance (d) between two points in 3 dimensions is ...
d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)
Then the distance between (a, -b, -4) and (0, 0, 0) is ...
d = √((a -0)² +(-b -0)² +(-4 -0)²)
= √(a² +b² +16)
Answer:
The rule or formula for the transformation of reflection across the line l with equation y = -x will be:
P(x, y) ⇒ P'(-y, -x)
Step-by-step explanation:
Considering the point

If we reflect a point
across the line
with equation
, the coordinates of the point P flips their places and the sign of the coordinates reverses.
Thus, the rule or formula for the transformation of reflection across the line l with equation y = -x will be:
P(x, y) ⇒ P'(-y, -x)
For example, if we reflect a point, let suppose A(1, 3), across the line
with equation
, the coordinates of point A flips their places and the sign of the coordinates reverses.
Hence,
A(1, 3) ⇒ A'(-3, -1)
Break the figure into a triangle and a rectangle.
The triangle has a base of 6 and a height of 3, so the area is 6*3/2 = 18/2 = 9
The rectangle has a length of 5 and a height of 6, so 6*5 = 30 is the area of the rectangle.
The total area is 30+9 = 39
Answer: 39