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jeka94
3 years ago
11

How do you write in slope intercept with only the rate of change and one point. Like rate of change is -5 and the point is (3,0)

Mathematics
1 answer:
Simora [160]3 years ago
5 0

Answer:

A linear equation in the slope-intercept form is written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

Now, we know that the rate of change (the slope) is -5

Then we just replace a by -5

y = -5*x + b

Now we also know that this line passes through a point, and the point is (3, 0)

This means that the point (3, 0) is a solution for the line equation, so when x = 3, we also have y = 0.

Replacing these values in our equation we get:

0 = -5*3 + b

0 = -15 + b

15 = b

Now we know the value of b, so we can replace it in the line equation to get:

y = -5*a + 15

Which is the complete equation of the line.

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The x-intercept of the function g(x) = -5(x - 3)^2 is (3, 0) and the vertex of the function g(x) = -5(x - 3)^2 is (3, 0)

<h3>How to determine the x-intercept?</h3>

The function is given as:

g(x) = -5(x - 3)^2

Set g(x) to 0, to determine the x-intercept.

-5(x - 3)^2 = 0

Divide through by -5

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Hence, the x-intercept of the function g(x) = -5(x - 3)^2 is (3, 0)

<h3>How to determine the vertex?</h3>

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g(x) = -5(x - 3)^2

A quadratic function is represented as:

g(x) = a(x - h)^2 + k

Where, the vertex is

Vertex = (h, k)

By comparing g(x) = a(x - h)^2 + k and g(x) = -5(x - 3)^2, we have

(h, k) = (3, 0)

Hence, the vertex of the function g(x) = -5(x - 3)^2 is (3, 0)

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