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Genrish500 [490]
2 years ago
13

HELPPPPPPPPPPPPPPPPPPPPP

Mathematics
2 answers:
cupoosta [38]2 years ago
7 0
A the answer is Density because after plugging a series of numbers in the results are for that of density
Vesna [10]2 years ago
5 0

Answer:

Angles

Step-by-step explanation:

A polygon is a shape, I don't think there are conversions since a polygon is not something you can measure. A population can be counted with normal numbers, 1,2,3... density is calculated with mass and volume, not radians and degrees.... yeah.

Angles are measured in radians and degrees, so it's angles.

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To divide 572 divide 4, Stanley estimated to place the first digit of the quotient. In which place is the first digit of the quo
andreyandreev [35.5K]
It would go over the five, so im guessing the hundreds

6 0
3 years ago
2 less than five times a number.
Reika [66]

Answer:

X will be the number.  

5 times that number X is 5X

2 less than 5 times the number is 5X - 2

Hope this helps! Plz mark brainliest! (づ ̄3 ̄)づ╭❤~

8 0
3 years ago
Read 2 more answers
Questions 1-6 of 6 | Page 1 of 1
LenKa [72]

Answer:

Blank 1 = 53 + 90 = 143

Blank 2 = 143 - 229 = -86

Blank 3 = 0 - 86 = 86

7 0
3 years ago
Karin has 7 more pieces of candy than Danny. Danny has d pieces of candy. Karin uses the expression 7 + d to figure out how many
mr Goodwill [35]

Answer:B

Step-by-step explanation:

If d=4 and Danny has 7 more peices all you have to do is multiply. 7x4 and that equals 28

So the final answer is 28 which is choice B

8 0
2 years ago
A box contains one yellow, two red, and three green balls. Two balls are randomly chosen without replacement. Define the followi
Stels [109]

Answer:

One of the balls is yellow: 0.36

At least one ball is red:0.73

Both balls are green:0.3

Both balls are of the same color:0.266

Step-by-step explanation:

To get the probability equally likely of choosing balls we use the following formula

P=# of possibilities that meet the condition / #of equally likely possibilities.

#of equally likely possibilities of the first experiment is 1+2+3=6

#of equally likely possibilities of the second experiment is 1+2+3 -1 =5 ( no replacement)

We choose 2 balls so we have to multiple  or add the probability of the 2 experiments,  that depends on the case

One of the balls is yellow:

1 experiment P{ One of the balls is yellow }= 1/6

2 experiment P{ One of the balls is yellow }= 1/5

P{ One of the balls is yellow }= 1/6+1/5=11/30

At least one ball is red:

1 experiment P{ One of the balls is red }= 2/6

2 experiment P{ One of the balls is red }= 2/5

P{ One of the balls is yellow }= 2/6+2/5=22/30

Both balls are green:

1 experiment P{ Both balls are green }= 3/6

2 experiment P{ Both balls are green }= 3/5

P{ Both balls are green }= 3/6*3/5=0.3

Both balls are of the same color

1 experiment P{ Both balls are green }= 3/6

2 experiment P{ Both balls are green }= 2/5

P{ Both balls are green }= 3/6*2/5=0.2

1 experiment P{ Both balls are red }= 2/6

2 experiment P{ Both balls are red }= 1/5

P{ Both balls are red }= 3/6*3/5=0.066

Both could happens so we add the probabilities

P{ Both balls are of the same color }=0.2+0.066=0.266

8 0
3 years ago
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