Given:
t A = 2.4 h
t B = 4 h
v A = 22 + v B
Solution:
Distance A and distance B is the same, distance could be defined using formula d = v × t
d A = d B
(v A × t A) = (v B × t B)
plug in the numbers
v A × 2.4 = v B × 4
(22 + vB) × 2.4 = 4 vB
remove the parenthesis using distributive property
(22 × 2.4) + (2.4 × vB) = 4vB
52.8 + 2.4vB = 4vB
add like terms
52.8 = 4vB - 2.4vB
52.8 = 1.6vB
52.8/1.6 = vB
vB = 33
the speed of car B is 33 mph
vA = 22 + vB
vA = 22 + 33
vA = 55
the speed of car A is 55 mph
Answer:
All statements are true.
Step-by-step explanation:
In a square, we have
all sides equal
all angles equal to 90 degrees
diagonals always bisect each other and at right angles.
Only square is the quadrilateral which satisfies all the above properties.
A parallelogram has diagonals which do not cut at right angles.
A rhombus has all sides equal but not all angles. Neither diagonals are equal in a rhombus.
Step 1 is to find how far apart W and Y are:
-7 - (-31) = 24
Now find 1/8 of that distance: 1/8 • 24 = 3
Now move 3 units from -31 towards -7: -31 + 3 = -28
Answer:
comment the question I will try to solve it.....
The answer is possibly 10
