F⁻¹(x) is the notation for the inverse of an equation, so you just need to find the inverse equation. that's found by swapping your x and y variables:
<span>f(x) = 2x + 2 ... replace f(x) with y
y = 2x + 2 ... swap x and y variables
x = 2y + 2 ... solve for y
x = 2y + 2 ... subtract 2
x - 2 = 2y ... divide by 2
(x - 2)/2 = y
so, </span>f⁻¹(x) = (x - 2)/2 ... now you need to solve that for when x = 4. plug it in:
f⁻¹(x) = (4 - 2)/2 ... simplify the top of the fraction
f⁻¹(x) = 2/2
f⁻¹(x) = 1 is your answer.
u multiply each number with the number diagonal to it!
the area is half of the products of the numbers which were multiplied to the numbers SE to them minus the products of numbers which were multiplied to numbers southwest to them
Ok i dont know the anwser but go to tiger algerbra and get the anwser there i hope you have a nice day
Answer:
5%
Step-by-step explanation:
<u>price after discount :</u>
9 600 - 9 600×40%
= 5760
<u>Original price (price without profit) :</u>
let x be the original price of the device.
x + x × 20% = 5760
Then
x = (5 760×100)÷120
= 4 800
<u>Original price increased by 30% :</u>
4 800 + 4 800×30%
= 6 240
<u>the discount needed to increase the profit by 10% :</u>
[(9 600-6 240)÷9 600]×100
= 35%
Then
to increase the profit by 10% ,we have to reduce
the percent of discount to :
40% - 35%
= 5%
Answer:
Step-by-step explanation:
An eigenvalue of n × n is a function of a scalar 
considering that there is a solution (i.e. nontrivial) to an eigenvector x of Ax =
Suppose the matrix ![A = \left[\begin{array}{cc}-1&-1\\2&1\\ \end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%26-1%5C%5C2%261%5C%5C%20%5Cend%7Barray%7D%5Cright%5D)
Thus, the equation of the determinant (A - 1) = 0
This implies that:
![\left[\begin{array}{cc}-1-\lambda &-1\\2&1- \lambda\\ \end{array}\right] =0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1-%5Clambda%20%26-1%5C%5C2%261-%20%5Clambda%5C%5C%20%5Cend%7Barray%7D%5Cright%5D%20%3D0)
Hence, the eigenvalues of the equation are 
Also, the eigenvalues can be said to be complex numbers.
