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erastova [34]
3 years ago
6

A television at Walmart cost $1,538 and $1,923 at Target. With taxes, what would you actually pay at each store. Walmart sales t

ax is 7% and Target’s sale tax is 9%.
Mathematics
1 answer:
mamaluj [8]3 years ago
8 0

Answer:

walmart:1645.66 target:2096.07

Step-by-step explanation:

walmart:1538/100 × 107= 1645.66

target:1923/100 × 109= 2096.07

i think this is the ans but im not very sure

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Urgent help need it plz​
Tatiana [17]

Answer:

angle 1 = 51

angle 2 = 34

angle 3 = 95

angle 4 = 38

angle 5 = 47

angle 6 = 74

angle 7 = 59

Step-by-step explanation:

a straight line is 180 degree, so to find angle 1, subtract 129 by 180.

angle 2 is found by adding angle 1 and 95 then subtract that by 180.

angle 3 and 95 are opposite angles, so they are the same

for angle 4, add angle three and 47 then subtract that by 180

angle 5 is 47, they are opposite

angle 7, subtract 121 by 180

angle 6, you add angle 5 and 7, and subtract that by 180

4 0
3 years ago
Read 2 more answers
HELP PLEASE WILL GIVE BRAINLIST IF CORRECT
Nat2105 [25]

Answer:

a.) First check on the height of the bar that ranges between 20 and 24 which is 6. The 6 is the number of students who bought 20 books or more, so get the percentage of those students who bought 20 or more books; divide 6 which is the number of students who bought 20 books or more with the total number of students which is 40 then multiply with 100.

% of students who bought 20 or more books = 6/40 ×100

=15

Step-by-step explanation:

b.) Find the area of a trapezium

= 1/2 × {a+b} × h

= 1/2 × {9 + 13} ×12

= 132

= 1/2 × {13 + 6} × 12

= 108

Mean no. of books bought = 132 + 108

= 240

4 0
3 years ago
The costs of four different containers of detergent are given in the
igomit [66]
You need to give me the table to help you
8 0
3 years ago
Simplifying Rational Expressions
Evgen [1.6K]
B^-2 / b^-3  = b^(-2-(-3) = b^1  = b

answer is d
4 0
3 years ago
What are the zeros of the quadratic function f(x) = 6x ^ 2 - 24x + 1 ?
ZanzabumX [31]

Answer:

x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}

Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: x=\frac{-b+\sqrt{b^2-4ac} }{2a} or x=\frac{-b-\sqrt{b^2-4ac} }{2a}.

Here, a = 6, b = -24, and c = 1. Plug these in:

x=\frac{-b+\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)+\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24+\sqrt{552} }{12}=\frac{24+2\sqrt{138} }{12} =\frac{12+\sqrt{138} }{6}

AND

x=\frac{-b-\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)-\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24-\sqrt{552} }{12}=\frac{24-2\sqrt{138} }{12} =\frac{12-\sqrt{138} }{6}

Thus, the zeroes are: x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}.

3 0
3 years ago
Read 2 more answers
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