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3 years ago

Which expression is equivalent to 3√50 × √22 ?

Mathematics

1 answer:

8_murik_8 [283]3 years ago

5 0

$\longrightarrow{\green{C.\:30 \sqrt{11} }}$ ✔

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$3 \sqrt{50} \times \sqrt{22} \\ \\ = 3 \sqrt{50 \times 22} \\ \\ = 3 \sqrt{1100} \\ \\ = 3 \sqrt{2 \times 2 \times 5 \times 5 \times 11} \\ \\ = 3 \sqrt{ {2}^{2} \times {5}^{2} \times 11} \\ \\ = 3 \times 2 \times 5 \sqrt{11} \\\\ = 30 \sqrt{11}$

$\bold{ \green{ \star{ \orange{Mystique35}}}}⋆$

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Mamont248 [21]

Answer:

x= 12.64

Step-by-step explanation:

3 0

3 years ago

School is making digital backups of old reels of film in its library archives the table shown approximate run Times of the films

Gemiola [76]

One technique that you can apply when solving such a problem is trial and error. We try to use each equation to prove that a given value of x on the table given will correspond to the value of y on the table.

a) Let's try to put x = 3 for the first equation and we must get an answer equal to 2.25.

$y=7.72(3)-29.02=-5.86_{}$

Since the value of y is not equal to 2.25 and the deviation is too large. this equation is not a good model,

b) We put x = 3 on the second equation and solve for y

$y=-7.52(3)^2+0.19(3)+3.26=-63.85$

Since the value of y is not equal to 2.25 and the deviation is too large. this equation is not a good model,

c) We put x = 3 on the third equation and solve for y,

$y=0.4(3)^2+0.79(3)-4.93=1.04$

Again, the value that we get is not equal to 2.25, hence, this equation is not a good model. But since its value is close to 2.25, we try to other values of x. If x = 5, we get

$y=0.4(5)^2+0.79(5)-4.93=9.02$

which has a slight deviation on the given value of y on the table for x = 5. let's try for x = 7. We have

$y=0.4(7)^2+0.79(7)-4.93=20.2$

and the answer has a small deviation compared to the actual value given. The other values of x can again be put on the equation and check their corresponding value of y, and the resulting values are as follows

$\begin{gathered} y=0.4(8)^2+0.79(8)-4.93=26.99 \\ y=0.4(12)^2+0.79(12)-4.93=62.15 \\ y=0.4(14)^2+0.79(14)-4.93=84.53 \end{gathered}$

And as you can see, the deviation of values from the table to calculated becomes smaller. Hence, this is the best model.

d) We put x = 3 on the third equation and solve for y,

$y=4.19(1.02)^3=4.45_{}_{}$

Again, the value that we get is not equal to 2.25, hence, this equation is not a good model. But since its value is close to 2.25, we try to other values of x. If x = 5, we get

$y=4.19(1.02)^5=4.63$

where the answer's deviation is too large compared to the value of y if x = 5 on the table given.

Based on the calculations used above, the best equation that can be a good model is equation 3.

5 0

1 year ago

20pts Please help! Asap Visitor attendance at the nature center in December is one-quarter the attendance in September. In Decem

Leya [2.2K]

Answer: I am in 6th grade and I just did this test too at K12 CAVA. I got the answer correct, it is:

376

Hope this helps.

3 0

3 years ago

An alloy consists of nickel, zinc, and copper in the ratio 2:7:9. How much alloy can be produced using 4.9 lb of zinc?

Wittaler [7]

Ratio of Nickel to Zinc:

( 2/7 ) = ( Nickel /4.9)

Nickel = 1.4 lbs.

Ratio of Copper to Zinc:

( 9/7 ) = ( Copper /4.9)

Copper = 6.3 lbs.

Alloy = Zinc + Nickel + Copper

Alloy = 4.9 lbs. + 1.4 lbs. + 6.3 lbs.

Alloy = 12.6 lbs.

Hope this answer will be a good help for you.

8 0

3 years ago

Solve the equation below 9 = x/18 x= What is X?

dedylja [7]

X=162, if you multiply 18*9 which is the way to get the answer you get 162

7 0

3 years ago