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3 years ago

A metal bar weighs 9.65 ounces. 78% of the bar is Gold. How many ounces of

Mathematics

1 answer:

Alecsey [184]3 years ago

3 0

Answer: 7.527 oz

Step-by-step explanation: 78%= 0.78

Mass of gold is 0.78 · 9.65 oz = 7.527 oz

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WILL GIVE BRAINIEST 100 PIONTS

antiseptic1488 [7]

Liar. This is only worth 5 points!!!!!!!!!!!!!!!!!!!!

4 0

4 years ago

The most recent census for a city indicated that there were 919,716 residents. The population of the city is expected to increas

OLEGan [10]

Answer:

1,474,951.

Step-by-step explanation:

Given a population that increases by a constant percentage, we can model the population's growth using the exponential model.

$P(t)=P_o(1+r)^t,$ where \left\{\begin{array}{lll}P_o=$Initial Population\\r$=Growth rate\\$t=time (in years)\end{array}\right\\P_o=919,716\\r=3.7\%=0.037\\$t=13 years$

Therefore, the population of the city in 13 years time will be:

$P(t)=919,716(1+0.037)^{13}\\\\=919,716(1.037)^{13}\\\\=1,474,950.9\\\\\approx 1,474,951$

The population be at that time will be approximately 1,474,951.

3 0

4 years ago

Write an recursive formula for An, the nth term of the sequence<br> 5, -2, -9,

oksian1 [2.3K]

Given:

The given sequence is:

$5,-2,-9,...$

To find:

The recursive formula for $a_n$ , the nth term of the sequence.

Solution:

We have,

$5,-2,-9,...$

Here, the first term is 5.

$-2-5=-7$

$-9-(-2)=-9+2$

$-9-(-2)=-7$

The common difference is -7.

The recursive formula for the nth term of the sequence is

$a_n=a_{n-1}+d$

Where, $d$ is the common difference.

Putting $d=-7$ in the above formula, we get

$a_n=a_{n-1}+(-7)$

$a_n=a_{n-1}-7$

Therefore, the recursive formula for the nth term of the sequence is $a_n=a_{n-1}-7$ .

3 0

3 years ago

Solve the inequality.<br> -12 < 1/2(x+16) < 18

lana66690 [7]

Answer:

-40 < x < 20

Step-by-step explanation:

step 1: -12 < 1/2(x+16) < 18 --> Distribute

step 2: -12 < 1/2x + 8 < 18 --> subtract 8

step 3: -20 < 1/2x < 10 --> Multiply by 2

answer : -40 < x < 20

3 0

3 years ago

If you stacked Avogadro's number of pennies one on top of the other on Earth's surface, how far would the stack extend (in kilom

miskamm [114]

Answer:my

The height of the stack will be 9.15×10^20_m

Or 9.15×10^17_Km

Which is 6 billion times more more than the distance to the sun

Or 22.9 million times further than the star Proxima Centauri

Step-by-step explanation:

Given

Avogadro's number = 6.02×10^23 particles

And the thickness of a penny = 1.52_mm

The height of the stack will be

1.52 × 6.02 ×10^23 = 9.15×10^23_mm 9.15×10^20_m

7 0

4 years ago