Answer:
4y + 24
Step-by-step explanation:
4(y + 6)
(4 * y) + (4 * 6)
(4y) + (24)
4y + 24
Answer:
<em>consecutive </em><em>mult</em><em>iple</em><em> </em><em>of</em><em> </em><em>2</em><em> </em><em>is</em><em> </em><em>2</em><em>,</em><em>4</em><em>,</em><em>6</em><em> </em>
<em>this</em><em> </em><em>sum</em><em> </em><em>is</em><em> </em><em>2</em><em>+</em><em>4</em><em>+</em><em>6</em><em> </em><em>is</em><em> </em><em>1</em><em>2</em>
<h3>
Answer: Choice D) -$22</h3>
You'll lose on average $22 per roll.
====================================================
Explanation:
Normally there is a 1/6 chance to land on any given side of a standard die, but your friend has loaded the die in a way to make it have a 40% chance to land on "1" and an equal chance to land on anything else. Since there's a 40% chance to land on "1", this leaves 100% - 40% = 60% for everything else.
Let's define two events
- A = event of landing on "1".
- B = event of landing on anything else (2 through 6).
So far we know that P(A) = 0.40 and P(B) = 0.60; I'm using the decimal form of each percentage.
The net value of event A, which I'll denote as V(A), is -100 since you pay $100 when event A occurs. So we'll write V(A) = -100. Also, we know that V(B) = 30 and this value is positive because you receive $30 if event B occurs.
To recap things so far, we have the following:
- P(A) = 0.40
- P(B) = 0.60
- V(A) = -100
- V(B) = 30
Multiply the corresponding probability and net value items together
- P(A)*V(A) = 0.40*(-100) = -40
- P(B)*V(B) = 0.60*30 = 18
Then add up those products:
-40+18 = -22
This is the expected value, and it represents the average amount of money you earn for each dice roll. So you'll lose on average about $22. Because the expected value is not zero, this means this game is not mathematically fair.
This does not mean that any single die roll you would lose $22; instead it means that if you played the game say 1000 or 10,000 times, then averaging out the wins and losses will get you close to a loss of $22.
The question is so dry, mechanical, and devoid of emotion
that it's terrifying.
There is no way to assign a number to "How many people were
dying per day", and I would prefer not even to think about it in
those terms.
-- The period of time from August 4, 1914 until November 11, 1918 is 1,560 days.
-- The "average", or better, the "unit rate" of 10 million events in 1,560 days
is the quotient
(10,000,000 events) / (1,560 days)
= 6,410.3 events per day
= 267.1 events per hour
= 4.45 events per minute.
Reciprocally, this is a unit rate of
13.48 seconds per event,
sustained continuously for 4.274 years !
When will we ever learn ! ?