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Scorpion4ik [409]
3 years ago
5

Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably norma

lly distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used.
Find the endpoints of the t-distribution with 2.5% beyond them in each tail if the samples have sizes n1=16 and n2=21.
Enter the exact answer for the degrees of freedom and round your answer for the endpoints to two decimal places.
Mathematics
1 answer:
ollegr [7]3 years ago
4 0

Answer:

Don't go on that link its a virus

Step-by-step explanation:

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Help help math math math
Marianna [84]

Answer:

3

Step-by-step explanation:

Get rid of fractions:

Multiply the whole equation, i.e. all terms both sides of the equals sign, by the denominator or the lowest common multiple of all denominators if there are multiple fractions in the equation;

In this case, only one term is a fraction and therefore has a denominator (i.e. 7), so it is this number we multiply the equation by to get:

7(y) = 7(-³/₇.x) + 7(3)

7y = -3x + 21

3x + 7y = 21

5 0
2 years ago
Pls answer this . I need help
madreJ [45]

Answer:

The ans is -14 if you use desmos and start "finger counting" the slope of -3, y will equal -14 once it reaches (3,y)

3 0
3 years ago
What is the equation of the line that is perpendicular to the given line and passes through the point (5,3)
Pani-rosa [81]

perpendicular lines have a slope that is a negative reciprocal


A) 4x-5y=5

subtract 4x

solve for y

-5y = -4x+5

divide by -5

y = 4/5 x+5   slope is 4/5  perpendicular slope is -5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = -5/4 (x-5)

B)  5x+4y = 37

subtract 5x

4y =-5x +37

divide by 4

y =-5/4 x +37/4  slope is -5/4 perpendicular slope is 4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = 4/5 (x-5)

C)4x+5y=5

subtract 4x

5y = -4x +5

divide by 5

y = -4/5 x +1

y =-4/5 x +1  slope is -4/5 perpendicular slope is 5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = 5/4 (x-5)

D)5x-4y=8

subtract 5x

-4y = -5x+8

divide by -4

y = 5/4 x-2

y =5/4 x +-2 slope is 5/4 perpendicular slope is -4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = -4/5 (x-5)



6 0
3 years ago
6. Find the perimeter of the figure below
liraira [26]

Answer:

26 in.

Step-by-step explanation:

» <u>Concepts</u>

The perimeter for a shape is the total distance around it measured in units. The formula to find the perimeter of a trapezoid is a + b + c + d, where a & b are the bases, and c & d are the lengths of the other sides.

» <u>Solution</u>

Adding up all the sides, we get:

  • 11+7+4+4
  • 18+4+4
  • 22+4
  • 26

26 inches

3 0
3 years ago
At what point of the curve y = cosh(x does the tangent have slope 2?
Dahasolnce [82]
The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444

Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
5 0
3 years ago
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