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Ivanshal [37]
2 years ago
6

What is the length of Line segment B C, rounded to the nearest tenth? 13. 0 units 28. 8 units 31. 2 units 33. 8 units.

Mathematics
1 answer:
Len [333]2 years ago
6 0

The length of the line segment BC is 31.2 units.

<h2>Given that</h2>

Triangle ABC is shown.

Angle ABC is a right angle.

An altitude is drawn from point B to point D on side AC to form a right angle.

The length of AD is 5 and the length of BD is 12.

<h3>We have to determine</h3>

What is the length of Line segment BC?

<h3>According to the question</h3>

The altitude of the triangle is given by;

\rm Altitude = \sqrt{xy}

Where x is DC and y is 5 units.

Then,

The length DC is.

\rm Altitude = \sqrt{xy}\\&#10;\\&#10;12 = \sqrt{(DC) \times 5}\\&#10;\\&#10;\sqrt{DC } = \dfrac{12}{\sqrt{5}}\\&#10;\\&#10;

Squaring on both sides

\rm DC = \dfrac{144}{5}\\&#10;\\&#10;DC = 28.8

Considering right triangle BDC, use the Pythagorean theorem to find BC:

\rm BC^2 = DC^2+BD^2\\\\  BC^2 = (28.8)^2+(12)^2\\&#10;&#10;\\&#10;BC = \sqrt{829.44+144}\\&#10;\\&#10;BC = \sqrt{973.44}\\&#10;\\&#10;\rm BC = 31.2 \ units

Hence, the length of the line segment BC is 31.2 units.

To know more about Pythagoras Theorem click the link given below.

brainly.com/question/26252222

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Answer:

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 48564, \sigma = 3293, n = 281, s = \frac{3293}{\sqrt{281}} = 196.44

What is the probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct?

This is the pvalue of Z when X = 48101. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{48101 - 48564}{196.44}

Z = -2.36

Z = -2.36 has a pvalue of 0.0091

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

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3 years ago
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AleksandrR [38]
I would say your answer is false because my mom works on houses and she never does this....

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<h2>{\orange {\boxed {\colorbox {black} {\orange {King\:Brainly01}}}}}</h2>

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»»————- ★ ————-««

I believe your answer is:  

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»»————- ★ ————-««  

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⸻⸻⸻⸻

See the graph attached.

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